- 能力傾向有用資源
- 能力傾向 - 問答
最大公約數和最小公倍數 - 線上測驗
以下測驗提供與最大公約數和最小公倍數相關的多項選擇題 (MCQ)。您需要閱讀所有給出的答案並點選正確的答案。如果您不確定答案，可以使用顯示答案按鈕檢視答案。您可以使用下一題按鈕在測驗中檢視新的問題集。
答案：C
解釋
72 = 23 x 32 108 = 22 x 33 2100 = 22 x 52 x 3 x7 Therefore L.C.M = 2 3 x 33 x 52 = 37800
答案：C
解釋
Greatest number of 4 digits is 9999. L.C.M of 15, 25, 400 and 75 is 600. On dividing 9999 by 600, the remainder is 399. Required number = (9999 - 399) = 9600.
答案：A
解釋
L.C.M of 6,9,15 and 18 is 90. Let required number be 90k + 4, which is a multiple of 7. Least value of k for which (90k + 4) is divisible by 7 is k = 4. Therefore Required number 90 x 4 + 4 = 364.
答案：B
解釋
Since the numbers are co-prime they contain only 1 as the common factor. Also the given two products have the middle number in common. So, the middle number = H.C.F of 551 and 1073 = 29; First number = 551⁄29 = 19; Third number = 1073⁄29 = 37 required sum = (19 + 29 + 37) = 85.
問題 5 - 一個長 3.78 米，寬 5.25 米的長方形庭院需要用相同尺寸的方形瓷磚鋪滿。可以使用的最大瓷磚尺寸是多少？
答案：A
解釋
Largest size of the tile = H.C.F of 378 cm and 525 cm = 21 cms.
答案：B
解釋
H.C.F. of given fractions = (H.C.F.of denominators)/(L.C.M.of numerators)=2/105 ( H.C.F.of numerators = 2 L.C.M.of denominators =105)
答案：D
解釋
Let the numbers be 5X, 6X and 7X Then, their L.C.M. = 210X. So, 210X = 2100 or X = 10. The numbers are (5 x 10), (6 x 10) and (7 x 10).Hence, required H.C.F. = 10.
答案：A
解釋
Let the numbers be x and y . Then,
{x+y= 45 , x= (1/9*45)= 5} ⇒x = 25, y =20
L.C.M of 25 and 20 = (5*5*4)= 100
答案：A
解釋
Let the two numbers be 5x and 7x . Then, their L.C.M is 35 x. 35x = 315 ⇒ x= 9 ∴ The numbers are 45 and 63 and their product is 2835.
答案：C
解釋
Required length = H.C.F of 700 cm, 385 cm and 1295 cm= 35 cm
aptitude_hcf_lcm.htm
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