Python Pandas - 如何對以秒為頻率的 DateTimeIndex 執行向上取整操作
要對以秒為頻率的 DateTimeIndex 執行向上取整操作,可以使用 **DateTimeIndex.ceil()** 方法。對於秒頻率,使用 **freq** 引數,其值為 **‘S’**。
首先,匯入所需的庫 -
import pandas as pd
建立一個週期為 5 且頻率為 S(即秒)的 DatetimeIndex -
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')顯示 DateTimeIndex -
print("DateTimeIndex...\n", datetimeindex)
對 DateTimeIndex 日期執行以秒為頻率的向上取整操作。對於秒頻率,我們使用了 'S' -
print("\nPerforming ceil operation with seconds frequency...\n",
datetimeindex.ceil(freq='S'))示例
以下是程式碼 -
import pandas as pd
# DatetimeIndex with period 5 and frequency as S i.e. seconds
# timezone is Australia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')
# display DateTimeIndex
print("DateTimeIndex...\n", datetimeindex)
# display DateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)
# getting the second
res = datetimeindex.second
# display only the second
print("\nThe second from DateTimeIndex...\n", res)
# Ceil operation on DateTimeIndex date with seconds frequency
# For seconds frequency, we have used 'S'
print("\nPerforming ceil operation with seconds frequency...\n",
datetimeindex.ceil(freq='S'))輸出
這將生成以下程式碼 -
DateTimeIndex... DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30', '2021-10-18 07:21:12.261811624+10:30', '2021-10-18 07:21:52.261811624+10:30', '2021-10-18 07:22:32.261811624+10:30', '2021-10-18 07:23:12.261811624+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='40S') DateTimeIndex frequency... <40 * Seconds> The second from DateTimeIndex... Int64Index([32, 12, 52, 32, 12], dtype='int64') Performing ceil operation with seconds frequency... DatetimeIndex(['2021-10-18 07:20:33+10:30', '2021-10-18 07:21:13+10:30', '2021-10-18 07:21:53+10:30', '2021-10-18 07:22:33+10:30', '2021-10-18 07:23:13+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq=None)
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