返回 NumPy 中非零且未掩蓋元素的索引,並按元素對索引進行分組
要返回非零且未掩蓋元素的索引,請在 NumPy 中使用 **ma.MaskedArray.nonzero()** 方法。要按元素對索引進行分組,我們在 transpose() 中使用了 nonzero() 方法。
返回一個元組,其中包含每個維度中非零元素的索引陣列。相應的非零值可以透過以下方式獲取 -
a[a.nonzero()]
要按元素而不是按維度對索引進行分組,請改用 -
np.transpose(a.nonzero())
其結果始終是一個二維陣列,其中每一行代表一個非零元素。
步驟
首先,匯入所需的庫 -
import numpy as np import numpy.ma as ma
使用 numpy.array() 方法建立一個包含整數元素的陣列 -
arr = np.array([[55, 85, 59, 77], [67, 33, 39, 57], [29, 88, 51, 37], [56, 45, 99, 85]])
print("Array...
", arr)
print("
Array type...
", arr.dtype)獲取陣列的維度 -
print("Array Dimensions...
",arr.ndim)
建立一個掩碼陣列,並將其中一些元素標記為無效 -
maskArr = ma.masked_array(arr, mask =[[1, 1, 0, 0], [ 0, 0, 1, 0], [0, 0, 0, 1], [0, 1, 0, 0]])
print("
Our Masked Array
", maskArr)
print("
Our Masked Array type...
", maskArr.dtype)獲取掩碼陣列的維度 -
print("
Our Masked Array Dimensions...
",maskArr.ndim)
獲取掩碼陣列的形狀 -
print("
Our Masked Array Shape...
",maskArr.shape)獲取掩碼陣列的元素數量 -
print("
Elements in the Masked Array...
",maskArr.size)
要返回非零且未掩蓋元素的索引,請在 NumPy 中使用 ma.MaskedArray.nonzero() 方法。返回一個元組,其中包含每個維度中非零元素的索引陣列。要按元素對索引進行分組,我們在 transpose() 中使用了 nonzero() 方法 -
print("
Result...
",np.transpose(maskArr.nonzero()))示例
import numpy as np
import numpy.ma as ma
# Create an array with int elements using the numpy.array() method
arr = np.array([[55, 85, 59, 77], [67, 33, 39, 57], [29, 88, 51, 37], [56, 45, 99, 85]])
print("Array...
", arr)
print("
Array type...
", arr.dtype)
# Get the dimensions of the Array
print("
Array Dimensions...
",arr.ndim)
# Create a masked array and mask some of them as invalid
maskArr = ma.masked_array(arr, mask =[[1, 1, 0, 0], [ 0, 0, 1, 0], [0, 0, 0, 1], [0, 1, 0, 0]])
print("
Our Masked Array
", maskArr)
print("
Our Masked Array type...
", maskArr.dtype)
# Get the dimensions of the Masked Array
print("
Our Masked Array Dimensions...
",maskArr.ndim)
# Get the shape of the Masked Array
print("
Our Masked Array Shape...
",maskArr.shape)
# Get the number of elements of the Masked Array
print("
Elements in the Masked Array...
",maskArr.size)
# To return the indices of unmasked elements that are not zero, use the ma.MaskedArray.nonzero() method in Numpy
# Returns a tuple of arrays, one for each dimension, containing the indices of the non-zero elements in that dimension.
# To and group the indices by element, we have used the nonzero() method in the transpose()
print("
Result...
",np.transpose(maskArr.nonzero()))輸出
Array... [[55 85 59 77] [67 33 39 57] [29 88 51 37] [56 45 99 85]] Array type... int64 Array Dimensions... 2 Our Masked Array [[-- -- 59 77] [67 33 -- 57] [29 88 51 --] [56 -- 99 85]] Our Masked Array type... int64 Our Masked Array Dimensions... 2 Our Masked Array Shape... (4, 4) Elements in the Masked Array... 16 Result... [[0 2] [0 3] [1 0] [1 1] [1 3] [2 0] [2 1] [2 2] [3 0] [3 2] [3 3]]
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