使用Python生成Hermite_e多項式的範德蒙德矩陣,其中包含複數點陣列


要生成Hermite_e多項式的範德蒙德矩陣,請在Python NumPy中使用hermite_e.hermvander()。此方法返回偽範德蒙德矩陣。返回矩陣的形狀為x.shape + (deg + 1,),其中最後一個索引是相應Hermite多項式的階數。dtype將與轉換後的x相同。

引數x返回點陣列。根據元素中是否存在複數,dtype將轉換為float64或complex128。如果x是標量,則將其轉換為一維陣列。引數deg是結果矩陣的階數。

步驟

首先,匯入所需的庫:

import numpy as np
from numpy.polynomial import hermite_e as H

建立一個數組:

x = np.array([-2.+2.j, -1.+2.j, 0.+2.j, 1.+2.j, 2.+2.j])

顯示陣列:

print("Our Array...\n",c)

檢查維度:

print("\nDimensions of our Array...\n",c.ndim)

獲取資料型別:

print("\nDatatype of our Array object...\n",c.dtype)

獲取形狀:

print("\nShape of our Array object...\n",c.shape)

要生成Hermite_e多項式的範德蒙德矩陣,請在Python NumPy中使用hermite_e.hermvander():

print("\nResult...\n",H.hermevander(x, 2))

示例

import numpy as np
from numpy.polynomial import hermite_e as H

# Create an array
x = np.array([-2.+2.j, -1.+2.j, 0.+2.j, 1.+2.j, 2.+2.j])

# Display the array
print("Our Array...\n",x)

# Check the Dimensions
print("\nDimensions of our Array...\n",x.ndim)

# Get the Datatype
print("\nDatatype of our Array object...\n",x.dtype)

# Get the Shape
print("\nShape of our Array object...\n",x.shape)

# To generate a Vandermonde matrix of the Hermite_e polynomial, use the hermite_e.hermvander() in Python Numpy
print("\nResult...\n",H.hermevander(x, 2))

輸出

Our Array...
   [-2.+2.j -1.+2.j 0.+2.j 1.+2.j 2.+2.j]

Dimensions of our Array...
1

Datatype of our Array object...
complex128

Shape of our Array object...
(5,)

Result...
   [[ 1.+0.j -2.+2.j -1.-8.j]
   [ 1.+0.j -1.+2.j -4.-4.j]
   [ 1.+0.j 0.+2.j -5.+0.j]
   [ 1.+0.j 1.+2.j -4.+4.j]
   [ 1.+0.j 2.+2.j -1.+8.j]]

更新於:2022年3月9日

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