使用Python生成Hermite_e多項式的範德蒙德矩陣,其中包含複數點陣列
要生成Hermite_e多項式的範德蒙德矩陣,請在Python NumPy中使用hermite_e.hermvander()。此方法返回偽範德蒙德矩陣。返回矩陣的形狀為x.shape + (deg + 1,),其中最後一個索引是相應Hermite多項式的階數。dtype將與轉換後的x相同。
引數x返回點陣列。根據元素中是否存在複數,dtype將轉換為float64或complex128。如果x是標量,則將其轉換為一維陣列。引數deg是結果矩陣的階數。
步驟
首先,匯入所需的庫:
import numpy as np from numpy.polynomial import hermite_e as H
建立一個數組:
x = np.array([-2.+2.j, -1.+2.j, 0.+2.j, 1.+2.j, 2.+2.j])
顯示陣列:
print("Our Array...\n",c)檢查維度:
print("\nDimensions of our Array...\n",c.ndim)獲取資料型別:
print("\nDatatype of our Array object...\n",c.dtype)獲取形狀:
print("\nShape of our Array object...\n",c.shape)要生成Hermite_e多項式的範德蒙德矩陣,請在Python NumPy中使用hermite_e.hermvander():
print("\nResult...\n",H.hermevander(x, 2))示例
import numpy as np
from numpy.polynomial import hermite_e as H
# Create an array
x = np.array([-2.+2.j, -1.+2.j, 0.+2.j, 1.+2.j, 2.+2.j])
# Display the array
print("Our Array...\n",x)
# Check the Dimensions
print("\nDimensions of our Array...\n",x.ndim)
# Get the Datatype
print("\nDatatype of our Array object...\n",x.dtype)
# Get the Shape
print("\nShape of our Array object...\n",x.shape)
# To generate a Vandermonde matrix of the Hermite_e polynomial, use the hermite_e.hermvander() in Python Numpy
print("\nResult...\n",H.hermevander(x, 2))輸出
Our Array... [-2.+2.j -1.+2.j 0.+2.j 1.+2.j 2.+2.j] Dimensions of our Array... 1 Datatype of our Array object... complex128 Shape of our Array object... (5,) Result... [[ 1.+0.j -2.+2.j -1.-8.j] [ 1.+0.j -1.+2.j -4.-4.j] [ 1.+0.j 0.+2.j -5.+0.j] [ 1.+0.j 1.+2.j -4.+4.j] [ 1.+0.j 2.+2.j -1.+8.j]]
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