PHP mysqli_stmt_error() 函式



定義和用法

mysqli_stmt_error() 函式返回執行最後一條語句期間發生的錯誤的描述。

語法

mysqli_stmt_error($stmt)

引數

序號 引數及描述
1

stmt(必填)

這是一個表示語句的物件。

返回值

PHP mysqli_stmt_error() 函式返回一個字串值,表示執行最後一條語句期間發生的錯誤的描述。如果沒有任何錯誤,此函式返回一個空字串。

PHP 版本

此函式首次引入於 PHP 5 版本,並在所有後續版本中均有效。

示例

以下示例演示了 mysqli_stmt_error() 函式(以過程式風格)的用法:

<?php
   $con = mysqli_connect("localhost", "root", "password", "mydb");

   mysqli_query($con, "CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
   print("Table Created.....\n");
   mysqli_query($con, "INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India')");
   print("Record Inserted.....\n");

   $stmt = mysqli_prepare($con, "SELECT * FROM myplayers");

   mysqli_query($con, "DROP TABLE myplayers");

   //Executing the statement
   mysqli_stmt_execute($stmt);

   //Error 
   $error = mysqli_stmt_error($stmt);
   print("Error : ".$error);

   //Closing the statement
   mysqli_stmt_close($stmt);

   //Closing the connection
   mysqli_close($con);
?>

這將產生以下結果:

Table Created.....
Record Inserted.....
Error : Table 'mydb.myplayers' doesn't exist

示例

在面向物件風格中,此函式的語法為 $con ->error。以下是此函式在面向物件風格中的示例:

<?php
   //Creating a connection
   $con = new mysqli("localhost", "root", "password", "mydb");

   $con -> query("CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
   print("Table Created.....\n");
   $con -> query("INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India')");
   print("Record Inserted.....\n");

   $stmt = $con ->prepare("SELECT * FROM myplayers");

   $con ->query("DROP TABLE myplayers");

   //Executing the statement
   $stmt->execute();

   //Error
   $error = $stmt ->error;
   print("Error: ".$error);

   //Closing the statement
   $stmt->close();

   //Closing the connection
   $con->close();
?>

這將產生以下結果:

Table Created.....
Record Inserted.....
Error : Table 'mydb.myplayers' doesn't exist

示例

如果最後執行的語句物件中沒有任何錯誤,則此函式返回一個空字串:

<?php
   $con = mysqli_connect("localhost", "root", "password", "mydb");

   mysqli_query($con, "CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
   print("Table Created.....\n");

   $query = "INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India'),(2, 'Jonathan', 'Trott', 'CapeTown', 'SouthAfrica'),(3, 'Kumara', 'Sangakkara', 'Matale', 'Srilanka')";

   //Preparing a statement
   $stmt = mysqli_prepare($con, $query);

   //Executing the statement
   mysqli_stmt_execute($stmt);
   print("Record Inserted.....\n");

   //Error 
   $error = mysqli_stmt_error($stmt);
   print("Error : ".$error);

   //Closing the statement
   mysqli_stmt_close($stmt);

   //Closing the connection
   mysqli_close($con);

?>

這將產生以下結果:

Table Created.....
Record Inserted.....
Error :
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