資料結構
網路
關係資料庫管理系統 (RDBMS)
作業系統
Java
MS Excel
iOS
HTML
CSS
Android
Python
C語言程式設計
C++
C#
MongoDB
MySQL
Javascript
PHP
物理學
化學
生物學
數學
英語
經濟學
心理學
社會學
服裝設計
法學C++程式計算sin(x)和cos(x)的值
給定角度作為輸入，任務是計算給定角度對應的sin(x)和cos(x)的值並顯示結果。
對於Sin(x)
Sin(x)是一個三角函式，用於計算x角的值。
公式
$$\sin (x) = \displaystyle\sum\limits_{k=0}^\infty \frac{(-1)^{k}}{(2k+1)!}x^{2k+1}$$
對於Cos(x)
Cos(x)是一個三角函式，用於計算x角的值。
公式
$$\cos (x) = \displaystyle\sum\limits_{k=0}^\infty \frac{(-1)^{k}}{(2k)!}x^{2k}$$
以下程式中使用的演算法如下 −
- 輸入sin(x)和cos(x)的x角的值
- 應用給定的sin(x)和cos(x)公式
- 列印結果
演算法
START Step 1-> declare function to calculate value of sin void cal_sin(float n) declare and set float acc = 0.0001, denominator, sinx, sinval Set n = n * (3.142 / 180.0) Declare float temp = n Set sinx = n Set sinval = sin(n) Declare and set int i = 1 DO set denominator = 2 * i * (2 * i + 1) set temp = -temp * n * n / denominator Set sinx = sinx + temp Set i = i + 1 While(acc <= fabs(sinval - sinx)) print sinx Step 2-> Declare function to calculate value of cos void cal_cos(float n) Declare and set float acc = 0.0001, temp, denominator, cosx, cosval Set n = n * (3.142 / 180.0) Set temp = 1 set cosx = temp set cosval = cos(n) Set int i = 1 Do set denominator = 2 * i * (2 * i - 1) Set temp = -temp * n * n / denominator Set cosx = cosx + temp Set i = i + 1 While(acc <= fabs(cosval - cosx)) print cosx Step 3-> In main() Declare float n = 30 Call cal_sin(n0 set n=60 Call cal_cos(n) STOP
示例
#include <iostream>
#include <math.h>
using namespace std;
//calculate value of sin
void cal_sin(float n) {
float acc = 0.0001, denominator, sinx, sinval;
n = n * (3.142 / 180.0); //convert in radian
float temp = n;
sinx = n;
sinval = sin(n);
int i = 1;
do {
denominator = 2 * i * (2 * i + 1);
temp = -temp * n * n / denominator;
sinx = sinx + temp;
i = i + 1;
} while (acc <= fabs(sinval - sinx));
cout<<sinx;
}
//calculate value of cos
void cal_cos(float n) {
float acc = 0.0001, temp, denominator, cosx, cosval;
n = n * (3.142 / 180.0); //convert in radiam
temp = 1;
cosx = temp;
cosval = cos(n);
int i = 1;
do {
denominator = 2 * i * (2 * i - 1);
temp = -temp * n * n / denominator;
cosx = cosx + temp;
i = i + 1;
} while (acc <= fabs(cosval - cosx));
cout<< cosx;
}
int main() {
float n = 30;
cout<<"value of Sin is : "; cal_sin(n);
cout<<"\n";
n=60;
cout<<"value of Cos is : ";
cal_cos(n);
return 0;
}輸出
value of Sin is : 0.500061 value of Cos is : 0.499847
更新於: 2019年11月20日
5K+ 次瀏覽
廣告