$$3\frac{1}{3} \ -\ \frac{2}{3}\left\{\frac{3}{10} \ +\ \frac{1}{2}\left( 3\ -\ \frac{3}{5}\right)\right\}$$
$\begin{array}{l}
3\frac{1}{3} \ -\ \frac{2}{3}\left\{\frac{3}{10} \ +\ \frac{1}{2}\left( 3\ -\ \frac{3}{5}\right)\right\}\\
\\
\\
=\ 3\frac{1}{3} \ -\ \frac{2}{3}\left\{\frac{3}{10} \ +\ \frac{1}{2}\left(\frac{15\ -\ 3}{5}\right)\right\}\\
\\
\\
=\ \frac{10}{3} \ -\ \frac{2}{3}\left\{\frac{3}{10} \ +\ \frac{1}{2}\left(\frac{12}{5}\right)\right\}\\
\\
\\
=\ \frac{10}{3} \ -\ \frac{2}{3}\left\{\frac{3}{10} \ +\ \frac{6}{5}\right\}\\
\\
\\
=\ \frac{10}{3} \ -\ \frac{2}{3}\left\{\frac{3\ +\ 12}{10}\right\}\\
\\
\\
=\ \frac{10}{3} \ -\ \frac{2}{3}\left\{\frac{15}{10}\right\}\\
\\
\\
=\ \frac{10}{3} \ -\ \frac{5}{5}\\
\\
\\
=\ \frac{10}{3} \ -\ 1\\
\\
\\
=\ \frac{10\ -\ 3}{3}\\
\\
\\
=\ \mathbf{\frac{7}{3}}
\end{array}$
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