MySQL - 根據日期進行 GROUP 和 COUNT?
你可以使用 GROUP BY 子句和 COUNT() 函式來實現。語法如下所示 −
SELECT yourColumnName1,yourColumnName2,..N,COUNT(*) as anyAliasName FROM yourTableName GROUP BY yourColumnName1,yourColumnName2;
為了理解上述語法,讓我們建立一個表。用於建立表的查詢如下 −
mysql> create table GroupAndCountByDate -> ( -> Id int NOT NULL AUTO_INCREMENT, -> TripDate date, -> ShopId int, -> PRIMARY KEY(Id) -> ); Query OK, 0 rows affected (0.79 sec)
現在,你可以使用 insert 命令在表中輸入一些記錄了。查詢如下 −
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-01-31',10);
Query OK, 1 row affected (0.52 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-02-01',15);
Query OK, 1 row affected (0.17 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-01-31',10);
Query OK, 1 row affected (0.23 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-02-01',15);
Query OK, 1 row affected (0.31 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-03-23',20);
Query OK, 1 row affected (0.15 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-04-21',25);
Query OK, 1 row affected (0.20 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-03-13',20);
Query OK, 1 row affected (0.16 sec)
mysql> insert into GroupAndCountByDate(TripDate,ShopId) values('2019-04-06',25);
Query OK, 1 row affected (0.17 sec)使用 select 語句顯示錶中的所有記錄。查詢如下 −
mysql> select *from GroupAndCountByDate;
以下是輸出 −
+----+------------+--------+ | Id | TripDate | ShopId | +----+------------+--------+ | 1 | 2019-01-31 | 10 | | 2 | 2019-02-01 | 15 | | 3 | 2019-01-31 | 10 | | 4 | 2019-02-01 | 15 | | 5 | 2019-03-23 | 20 | | 6 | 2019-04-21 | 25 | | 7 | 2019-03-13 | 20 | | 8 | 2019-04-06 | 25 | +----+------------+--------+ 8 rows in set (0.00 sec)
以下是按日期分組和計數的查詢 −
mysql> select TripDate,ShopId,COUNT(*) as TOTALTRIP -> from GroupAndCountByDate -> group by TripDate,ShopId;
以下是輸出 −
+------------+--------+-----------+ | TripDate | ShopId | TOTALTRIP | +------------+--------+-----------+ | 2019-01-31 | 10 | 2 | | 2019-02-01 | 15 | 2 | | 2019-03-23 | 20 | 1 | | 2019-04-21 | 25 | 1 | | 2019-03-13 | 20 | 1 | | 2019-04-06 | 25 | 1 | +------------+--------+-----------+ 6 rows in set (0.00 sec)
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