聚合:將巢狀文件中(巢狀物件)的日期分組並顯示計數?
對於聚合,在 MongoDB 中使用 aggregate()。使用 $group 將日期分組。讓我們建立一個包含文件的集合 −
> db.demo717.insertOne( ... { ... "shippingdetails": ... [ ... { ... duedate:"2020-04-29 22:33:04", ... }, ... { ... duedate:"2020-03-29 22:33:04", ... }, ... { ... duedate:"2020-04-29 22:33:04", ... }, ... { ... duedate:"2020-01-29 22:33:04", ... } ... ] ... } ... ); { "acknowledged" : true, "insertedId" : ObjectId("5ea9b3cd85324c2c98cc4c30") }
使用 find() 方法顯示集合中的所有文件 −
> db.demo717.find().pretty();
這會產生以下輸出 −
{ "_id" : ObjectId("5ea9b3cd85324c2c98cc4c30"), "shippingdetails" : [ { "duedate" : "2020-04-29 22:33:04" }, { "duedate" : "2020-03-29 22:33:04" }, { "duedate" : "2020-04-29 22:33:04" }, { "duedate" : "2020-01-29 22:33:04" } ] }
以下是將巢狀文件(巢狀物件)中日期分組的聚合查詢 −
> db.demo717.aggregate( ... { ... $unwind:"$shippingdetails"}, ... { ... $group: { ... _id: "$shippingdetails.duedate", ... count: { ... $sum: 1 ... } ... } ... } ... )
這會產生以下輸出 −
{ "_id" : "2020-01-29 22:33:04", "count" : 1 } { "_id" : "2020-03-29 22:33:04", "count" : 1 } { "_id" : "2020-04-29 22:33:04", "count" : 2 }
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