MongoDB SELECT 按組計數?
藉助聚合框架,您可以實現此目標。為了理解這個概念,讓我們建立一個帶文件的集合。用於使用文件建立集合的查詢如下:
> db.countGroupByDemo.insertOne({"StudentId":10,"StudentName":"John"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c7700871e9c5dd6f1f78296")
}
> db.countGroupByDemo.insertOne({"StudentId":10,"StudentName":"Carol"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c77008f1e9c5dd6f1f78297")
}
> db.countGroupByDemo.insertOne({"StudentId":20,"StudentName":"Sam"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c7700971e9c5dd6f1f78298")
}
> db.countGroupByDemo.insertOne({"StudentId":30,"StudentName":"Mike"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c7700a21e9c5dd6f1f78299")
}
> db.countGroupByDemo.insertOne({"StudentId":30,"StudentName":"David"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c7700aa1e9c5dd6f1f7829a")
}
> db.countGroupByDemo.insertOne({"StudentId":10,"StudentName":"Maxwell"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c7700b41e9c5dd6f1f7829b")
}
> db.countGroupByDemo.insertOne({"StudentId":20,"StudentName":"Bob"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c7700bd1e9c5dd6f1f7829c")
}透過使用 find() 方法顯示集合中的所有文件。查詢如下:
> db.countGroupByDemo.find().pretty();
輸出
{
"_id" : ObjectId("5c7700871e9c5dd6f1f78296"),
"StudentId" : 10,
"StudentName" : "John"
}
{
"_id" : ObjectId("5c77008f1e9c5dd6f1f78297"),
"StudentId" : 10,
"StudentName" : "Carol"
}
{
"_id" : ObjectId("5c7700971e9c5dd6f1f78298"),
"StudentId" : 20,
"StudentName" : "Sam"
}
{
"_id" : ObjectId("5c7700a21e9c5dd6f1f78299"),
"StudentId" : 30,
"StudentName" : "Mike"
}
{
"_id" : ObjectId("5c7700aa1e9c5dd6f1f7829a"),
"StudentId" : 30,
"StudentName" : "David"
}
{
"_id" : ObjectId("5c7700b41e9c5dd6f1f7829b"),
"StudentId" : 10,
"StudentName" : "Maxwell"
}
{
"_id" : ObjectId("5c7700bd1e9c5dd6f1f7829c"),
"StudentId" : 20,
"StudentName" : "Bob"
}以下是按組選擇計數的查詢:
> db.countGroupByDemo.aggregate([
... {"$group":{_id:"$StudentId",counter:{$sum:1}}}]);輸出
{ "_id" : 30, "counter" : 2 }
{ "_id" : 20, "counter" : 2 }
{ "_id" : 10, "counter" : 3 }
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