使用 MongoDB 聚合按多個欄位計數
要按多個欄位計數,在 MongoDB 中使用 $facet。 $facet 在同一組輸入文件上對一個階段內多個聚合管道進行處理。讓我們建立一個包含文件的集合 −
> db.demo721.insertOne(
... {
...
... "details1": {
... "id":101
...
... },
... "details2": {
... "id":101
... },
... "details3": {
... "id":101
... }
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5eaaebdd43417811278f5887")
}
>
>
> db.demo721.insertOne(
... {
...
... "details1": {
... "id":101
...
... },
... "details2": {
... "id":102
... },
... "details3": {
... "id":102
... }
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5eaaebe943417811278f5888")
}在集合中顯示所有文件,使用 find() 方法 −
> db.demo721.find();
這將生成以下輸出 −
{ "_id" : ObjectId("5eaaebdd43417811278f5887"), "details1" : { "id" : 101 }, "details2" : { "id" : 101 }, "details3" : { "id" : 101 } }
{ "_id" : ObjectId("5eaaebe943417811278f5888"), "details1" : { "id" : 101 }, "details2" : { "id" : 102 }, "details3" : { "id" : 102 } }以下是按多個欄位計數的查詢 −
> db.demo721.aggregate([
... {$facet:{
... ids:[
... {$group:{ _id:null,
... d3:{$addToSet: "$details3.id"},
... d2:{$addToSet:"$details2.id"},
... d1:{$addToSet:"$details1.id"}}},
... {$project:{ _id:0,
... listofall:{$setUnion:["$d1","$d2","$d3"]}}}],
... d:[{$project:{ _id:0,
... a1:"$details1.id",
... a2:"$details2.id",
... a3:"$details3.id"}}]}},
... {$unwind:"$d"},
... {$unwind:"$ids"},
... {$unwind:"$ids.listofall"},
... {$group:{ _id:"$ids.listofall",
... details1id:{$sum:{$cond:[{$eq:["$d.a1","$ids.listofall"]},1,0]}},
... details2id:{$sum:{$cond:[{$eq:["$d.a2","$ids.listofall"]},1,0]}},
... details3id:{$sum:{$cond:[{$eq:["$d.a3","$ids.listofall"]},1,0]}}}}])這將生成以下輸出 −
{ "_id" : 102, "details1id" : 0, "details2id" : 1, "details3id" : 1 }
{ "_id" : 101, "details1id" : 2, "details2id" : 1, "details3id" : 1 }
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