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C++ unordered_map::swap() 函式
C++ 的 std::unordered_map::swap() 函式用於交換第一個 unordered_map 與另一個 unordered_map 的內容。當另一個容器型別相同的時候,交換才會發生。
此函式交換元素或鍵值對,而不會實際對單個元素執行任何複製或移動操作,從而無論大小都能實現常數時間執行。
語法
以下是 std::unordered_map::swap() 函式的語法。
void swap(unordered_map& ump);
引數
- ump − 指示要交換的容器。
返回值
此函式不返回任何值。
示例 1
在下面的示例中,讓我們看看 swap() 函式的用法。
#include <iostream> #include <unordered_map> using namespace std; int main(void) { unordered_map<char, int> um1 = { {'a', 1}, {'b', 2}, {'c', 3}, {'d', 4}, {'e', 5} }; unordered_map<char, int> um2; um1.swap(um2); cout << "Unordered map contains following elements" << endl; for (auto it = um2.begin(); it != um2.end(); ++it) cout << it->first << " = " << it->second << endl; return 0; }
輸出
讓我們編譯並執行上述程式,這將產生以下結果:
Unordered map contains following elements e = 5 a = 1 b = 2 c = 3 d = 4
示例 2
在下面的示例中,我們將執行兩個容器之間的交換,並將它們的值互換。
#include <iostream> #include <unordered_map> using namespace std; int main(void) { unordered_map<char, int> um1 = { {'a', 1}, {'b', 2}, {'c', 3}, {'d', 4} }; unordered_map<char, int> um2 = { {'e', 5}, {'f', 6}, {'g', 7}, {'h', 8} }; cout<<"um1 contains following element before swap: "<<endl; for(auto & it:um1){ cout<<it.first<< " = "<<it.second<<endl; } cout<<"um2 contains following element before swap: "<<endl; for(auto & it:um2){ cout<<it.first<< " = "<<it.second<<endl; } um1.swap(um2); cout << "um1 contains following elements after swap: " << endl; for (auto it = um1.begin(); it != um1.end(); ++it) cout << it->first << " = " << it->second << endl; cout << "um2 contains following elements after swap: " << endl; for (auto it = um2.begin(); it != um2.end(); ++it) cout << it->first << " = " << it->second << endl; return 0; }
輸出
以下是上述程式碼的輸出:
um1 contains following element before swap: d = 4 c = 3 b = 2 a = 1 um2 contains following element before swap: h = 8 g = 7 f = 6 e = 5 um1 contains following elements after swap: h = 8 g = 7 f = 6 e = 5 um2 contains following elements after swap: d = 4 c = 3 b = 2 a = 1
示例 3
考慮下面的示例,我們將建立一個兩個對映,一個使用 [] 運算子,另一個正常建立,然後交換它們的值。
#include <iostream> #include <unordered_map> using namespace std; int main(void) { unordered_map<string, int> um1; um1["Vivek"] = 80; um1["Aman"] = 85; um1["Akash"] = 90; unordered_map<string, int> um2 = { {"Sarika", 65}, {"Revathi", 95}, {"Daniel", 100} }; cout<<"um1 contains following element before swap: "<<endl; for(auto & it:um1){ cout<<it.first<< " = "<<it.second<<endl; } cout<<"um2 contains following element before swap: "<<endl; for(auto & it:um2){ cout<<it.first<< " = "<<it.second<<endl; } um1.swap(um2); cout << "um1 contains following elements after swap: " << endl; for (auto it = um1.begin(); it != um1.end(); ++it) cout << it->first << " = " << it->second << endl; cout << "um2 contains following elements after swap: " << endl; for (auto it = um2.begin(); it != um2.end(); ++it) cout << it->first << " = " << it->second << endl; return 0; }
輸出
上述程式碼的輸出如下:
um1 contains following element before swap: Akash = 90 Aman = 85 Vivek = 80 um2 contains following element before swap: Revathi = 95 Daniel = 100 Sarika = 65 um1 contains following elements after swap: Revathi = 95 Daniel = 100 Sarika = 65 um2 contains following elements after swap: Akash = 90 Aman = 85 Vivek = 80
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