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法律研究Python Pandas - 從 TimeDeltaIndex 建立一個 Series，並設定生成的 Series 的索引
使用**to_series()** 方法從 Pandas 中的 TimeDeltaIndex 建立一個 Series。**index** 引數用於設定生成 Series 的索引。
首先，匯入所需的庫 −
import pandas as pd
建立 TimeDeltaIndex 物件。我們使用“data”引數設定 timedelta 類似的資料 −
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 3us 10ns', '+22:39:19.999999', '2 day 4h 03:08:02.000045', '+21:15:45.999999'])
顯示 TimeDeltaIndex −
print("TimedeltaIndex...\n", tdIndex)
將 TimeDeltaIndex 轉換為 Series，並設定生成 Series 的索引。我們使用“index”引數設定了索引 −
print("\nTimeDeltaIndex to series with new index...\n",
tdIndex.to_series(index=['Date1','Date2','Date3','Date4']))示例
以下是程式碼 −
import pandas as pd
# Create a TimeDeltaIndex object
# We have set the timedelta-like data using the 'data' parameter
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 3us 10ns', '+22:39:19.999999',
'2 day 4h 03:08:02.000045', '+21:15:45.999999'])
# display TimedeltaIndex
print("TimedeltaIndex...\n", tdIndex)
# Return a dataframe of the components of TimeDeltas
print("\nThe Dataframe of the components of TimeDeltas...\n", tdIndex.components)
# Return TimeDeltaIndex as object ndarray
print("\nReturn TimeDeltaIndex as object ndarray of datetime.datetime objects...\n",
tdIndex.to_pytimedelta())
# Convert TimeDeltaIndex to Series and set the index of the resulting series
# We have set the index using the "index" parameter
print("\nTimeDeltaIndex to series with new index...\n",
tdIndex.to_series(index=['Date1','Date2','Date3','Date4']))輸出
這將生成以下程式碼 −
TimedeltaIndex... TimedeltaIndex(['10 days 05:02:00.000003010', '0 days 22:39:19.999999', '2 days 07:08:02.000045', '0 days 21:15:45.999999'], dtype='timedelta64[ns]', freq=None) The Dataframe of the components of TimeDeltas... days hours minutes seconds milliseconds microseconds nanoseconds 0 10 5 2 0 0 3 10 1 0 22 39 19 999 999 0 2 2 7 8 2 0 45 0 3 0 21 15 45 999 999 0 Return TimeDeltaIndex as object ndarray of datetime.datetime objects... [datetime.timedelta(days=10, seconds=18120, microseconds=3) datetime.timedelta(seconds=81559, microseconds=999999) datetime.timedelta(days=2, seconds=25682, microseconds=45) datetime.timedelta(seconds=76545, microseconds=999999)] TimeDeltaIndex to series with new index... Date1 10 days 05:02:00.000003010 Date2 0 days 22:39:19.999999 Date3 2 days 07:08:02.000045 Date4 0 days 21:15:45.999999 dtype: timedelta64[ns]
更新於：20-Oct-2021
209 次瀏覽
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