Python - 計算 Pandas DataFrame 中列值的最小值
若要獲取列值的最小值,請使用 min() 函式。首先,匯入所需的 Pandas 庫 -
import pandas as pd
現在,建立一個包含兩列的 DataFrame -
dataFrame1 = pd.DataFrame(
{
"Car": ['BMW', 'Lexus', 'Audi', 'Tesla', 'Bentley', 'Jaguar'],"Units": [100, 150, 110, 80, 110, 90] }
)使用 min() 查詢“Units”這一列的最小值 -
print"Minimum Units from DataFrame1 = ",dataFrame1['Units'].min()
使用相同的方式,我們從第二個 DataFrame 中計算最小值。
示例
以下為完整程式碼 -
import pandas as pd
# Create DataFrame1
dataFrame1 = pd.DataFrame(
{
"Car": ['BMW', 'Lexus', 'Audi', 'Tesla', 'Bentley', 'Jaguar'],"Units": [100, 150, 110, 80, 110, 90] }
)
print"DataFrame1 ...\n",dataFrame1
# Finding minimum value of a single column "Units"
print"Minimum Units from DataFrame1 = ",dataFrame1['Units'].min()
# Create DataFrame2
dataFrame2 = pd.DataFrame(
{
"Product": ['TV', 'PenDrive', 'HeadPhone', 'EarPhone', 'HDD', 'SSD'],"Price": [8000, 500, 3000, 1500, 3000, 4000]
}
)
print"\nDataFrame2 ...\n",dataFrame2
# Finding minimum value of a single column "Price"
print"Minimum Price from DataFrame2 = ",dataFrame2['Price'].min()輸出
以下為執行輸出 -
DataFrame1 ... Car Units 0 BMW 100 1 Lexus 150 2 Audi 110 3 Tesla 80 4 Bentley 110 5 Jaguar 90 Minimum Units from DataFrame1 = 80 DataFrame2 ... Price Product 0 8000 TV 1 500 PenDrive 2 3000 HeadPhone 3 1500 EarPhone 4 3000 HDD 5 4000 SSD Minimum Price from DataFrame2 = 500
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