MySQLi - 插入 ID

語法

mixed mysqli_insert_id ( mysqli $link )

定義和用法

它返回最近查詢中使用自動生成的 ID。

示例

嘗試執行以下示例 −

<?php
   $servername = "localhost:3306";
   $username = "root";
   $password = "";
   $dbname = "TUTORIALS";
   $conn = new mysqli($servername, $username, $password, $dbname);

   if ($conn->connect_error) {
      die('Connect Error (' . mysqli_connect_errno() . ') '. mysqli_connect_error());
      exit();
   } 
   if (!mysqli_query($conn, "SET a = 1")) {
      printf("Errorcode: %d\n", mysqli_error($conn));
   }
   echo 'Success... ' . mysqli_get_host_info($conn) . "\n";
   $sql = "CREATE TABLE tutorials_auto1 LIKE tutorials_auto";
   mysqli_query($conn,$sql);  
   
   $sql1 = "INSERT INTO tutorials_auto1 SELECT * FROM tutorials_auto ORDER BY name LIMIT 2";
   mysqli_query($conn,$sql1);
   printf ("New Record has id %d.\n", $conn->insert_id); 
   
   $conn->close();
?>

以上程式碼的示例輸出應如下 −

Errorcode: 0 Success... localhost:3306 via TCP/IP New Record has id 0.