在 C 中比較字串的程式

實現

現在，我們將檢視程式的實際實現 −

#include <stdio.h>

int main() {
   char s1[] = "advise";     
   char s2[] = "advice";
    
   int n = 0;
   unsigned short flag = 1; 
    
   while (s1[n] != '\0') {
      if(s1[n] != s2[n]) {
         flag = 0;
         break;
      }
      n++;
   }
    
   if(flag == 1) {
      printf("%s and %s are identical\n", s1, s2);
   } else {
      printf("%s and %s are NOT identical\n", s1, s2);
   }

   return 0;
}

輸出

此程式的輸出應為 −

advise and advice are NOT identical