C 語言阿姆斯壯數程式

阿姆斯壯數等於其各個數字的立方和。例如，153 是阿姆斯壯數，因為 -

153 = (1)3 + (5)3 + (3)3
153 = 1 + 125 + 27
153 = 153

演算法

此程式的演算法非常簡單 -

START
   Step 1 → Take integer variable Arms
   Step 2 → Assign value to the variable
   Step 3 → Split all digits of Arms
   Step 4 → Find cube-value of each digits
   Step 5 → Add all cube-values together
   Step 6 → Save the output to Sum variable
   Step 7 → If Sum equals to Arms print Armstrong Number
   Step 8 → If Sum not equals to Arms print Not Armstrong Number
STOP

虛擬碼

我們可以草擬以上演算法的虛擬碼，如下所示 -

procedure armstrong : number
   
   check = number
   rem   = 0
   
   WHILE check IS NOT 0
      rem ← check modulo 10
      sum ← sum + (rem)3
      divide check by 10
   END WHILE
      
   IF sum equals to number
      PRINT armstrong
   ELSE
      PRINT not an armstrong
   END IF

end procedure

實現

此演算法的實現如下。你可以更改 arms 變數的值，然後執行和檢查你的程式 -

#include <stdio.h>

int main() {
   int arms = 153; 
   int check, rem, sum = 0;

   check = arms;

   while(check != 0) {
      rem = check % 10;
      sum = sum + (rem * rem * rem);
      check = check / 10;
   }

   if(sum == arms) 
      printf("%d is an armstrong number.", arms);
   else 
      printf("%d is not an armstrong number.", arms);
      
   return 0;
}

輸出

程式的輸出應該是 -

153 is an armstrong number.