jQuery Mobile - 彈出選單

說明

在彈出容器中使用 data-role = "listview" 屬性建立選單。

示例

以下示例展示了在 jQuery Mobile 框架中使用 彈出選單。

<!DOCTYPE html>
<html>
   <head>
      <title>Popup Menu</title>
      <meta name = "viewport" content = "width = device-width, initial-scale = 1">
      <link rel = "stylesheet" href = "https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.css">
      <script src = "https://code.jquery.com/jquery-1.11.3.min.js"></script>
      <script src = "https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.js"></script>
   </head>

   <body>
      <div data-role = "page">
         <div data-role = "header">
            <h2>Header</h2>
         </div>
         
         <div id = "page1" data-role = "main" class = "ui-content">
            <a href = "#popup_menu" data-rel = "popup" data-transition = "slidedown" 
               class = "ui-btn ui-btn-inline ui-icon-home ui-btn-icon-left ui-btn-a">
               Click to see menu items</a>
               
            <div data-role = "popup" id = "popup_menu" data-theme = "a">
               <ul data-role = "listview">
                  <li data-role = "list-divider">Select your choice</li>
                  <li><a href = "#">India</a></li>
                  <li><a href = "#">Srilanka</a></li>
                  <li><a href = "#">Australia</a></li>
                  <li><a href = "#">England</a></li>
               </ul>
            </div>
         </div>
         
         <div data-role = "footer">
            <h2>Footer</h2>
         </div>
      </div>
      
   </body>
</html>

輸出

執行以下步驟，瞭解上述程式碼如何工作：

將上述 html 程式碼儲存為 jqm_popup_menu.html 檔案，並放在伺服器根資料夾中。
以 https:///jqm_popup_menu.html 開啟此 HTML 檔案，隨後將顯示以下輸出。

jquery_mobile_widgets.htm

列印頁面

上一個

下一個