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法律研究執行圖的邊緣著色的 C++ 程式
在本程式中，我們將執行圖的邊緣著色，其中我們必須給圖的邊緣著色，使得沒有兩條相鄰的邊具有相同的顏色。示例中的步驟。
演算法
Begin Take the input of the number of vertices, n, and then number of edges, e, in the graph. The graph is stored as adjacency list. BFS is implemented using queue and colors are assigned to each edge. End
示例
#include<bits/stdc++.h>
using namespace std;
int n, e, i, j;
vector<vector<pair<int, int> > > g;
vector<int> color;
bool v[111001];
void col(int n) {
queue<int> q;
int c = 0;
set<int> vertex_colored;
if(v[n])
return;
v[n] = 1;
for(i = 0;i<g[n].size();i++) {
if(color[g[n][i].second]!=-1) {
vertex_colored.insert(color[g[n][i].second]);
}
}
for(i = 0;i<g[n].size();i++) {
if(!v[g[n][i].first]) {
q.push(g[n][i].first);
}
if(color[g[n][i].second]==-1) {
while(vertex_colored.find(c)!=vertex_colored.end())
c++;
color[g[n][i].second] = c;
vertex_colored.insert(c);
c++;
}
}
while(!q.empty()) {
int temp = q.front();
q.pop();
col(temp);
}
return;
}
int main() {
int u,w;
set<int> empty;
cout<<"Enter number of vertices and edges respectively:";
cin>>n>>e;
cout<<"\n";
g.resize(n); //number of vertices
color.resize(e,-1); //number of edges
memset(v,0,sizeof(v));
for(i = 0;i<e;i++) {
cout<<"\nEnter edge vertices of edge "<<i+1<<" :"<<"\n";
cin>>u>>w;
u--; w--;
g[u].push_back(make_pair(w,i));
g[w].push_back(make_pair(u,i));
}
col(0);
for(i = 0;i<e;i++) {
cout<<"Edge "<<i+1<<" is coloured with colour "<<color[i]+1
<< "\n";
}
}輸出
Enter number of vertices and edges respectively:4 5 Enter edge vertices of edge 1 :1 2 Enter edge vertices of edge 2 :2 3 Enter edge vertices of edge 3 :1 1 Enter edge vertices of edge 4 :3 4 Enter edge vertices of edge 5 :1 4 Edge 1 is coloured with colour 1 Edge 2 is coloured with colour 2 Edge 3 is coloured with colour 2 Edge 4 is coloured with colour 1 Edge 5 is coloured with colour 3
更新於：2019 年 7 月 30 日
541 次瀏覽
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