Python – 如何檢查 Pandas 中缺少日期


要檢查缺少的日期,首先,讓我們設定一個帶有日期記錄的列表字典,即我們示例中的購買日期 −

# dictionary of lists
d = {'Car': ['BMW', 'Lexus', 'Audi', 'Mercedes', 'Jaguar', 'Bentley'],
   'Date_of_purchase': ['2020-10-10', '2020-10-12', '2020-10-17', '2020-10-16', '2020-10-19', '2020-10-22']}

現在,從上述列表字典中建立一個數據框架 −

dataFrame = pd.DataFrame(d)

接下來,將其設定為索引 −

dataFrame = dataFrame.set_index('Date_of_purchase')

使用 to_datetime() 將字串轉換為 DateTime 物件 −

dataFrame.index = pd.to_datetime(dataFrame.index)

顯示範圍內的剩餘日期 −

k = pd.date_range( start="2020-10-10", end="2020-10-22").difference(dataFrame.index);

示例

以下是程式碼 −

import pandas as pd

# dictionary of lists
d = {'Car': ['BMW', 'Lexus', 'Audi', 'Mercedes', 'Jaguar', 'Bentley'],
   'Date_of_purchase': ['2020-10-10', '2020-10-12', '2020-10-17', '2020-10-16', '2020-10-19', '2020-10-22'] }

# creating dataframe from the above dictionary of lists
dataFrame = pd.DataFrame(d)
print"DataFrame...\n",dataFrame

# Date_of_purchase set as index
dataFrame = dataFrame.set_index('Date_of_purchase')

# using to_datetime() to convert string to DateTime object
dataFrame.index = pd.to_datetime(dataFrame.index)

# remaining dates displayed as output
print("\nDisplaying remaining dates from a range of dates...")
k = pd.date_range(start="2020-10-10", end="2020-10-22").difference(dataFrame.index);

print(k);

輸出

這將產生以下輸出 −

DataFrame...
         Car    Date_of_purchase
0       BMW           2020-10-10
1     Lexus           2020-10-12
2      Audi           2020-10-17
3  Mercedes           2020-10-16
4    Jaguar           2020-10-19
5   Bentley           2020-10-22

Displaying remaining dates from a range of dates...
DatetimeIndex(['2020-10-11', '2020-10-13', '2020-10-14', '2020-10-15',
   '2020-10-18', '2020-10-20', '2020-10-21'],
   dtype='datetime64[ns]', freq=None)

更新於:09-Sep-2021

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