MongoDB 中 $addToSet 的反義詞是 '$removeFromSet' 嗎?
要獲得 $addToSet 的相反操作 '$removeFromSet', 請使用 $pull 運算子。
讓我們建立一個包含文件的集合。建立包含文件的集合的查詢如下 -
> db.oppositeAddToSetDemo.insertOne({"StudentName":"John","StudentHobby":["Cricket","Cooking","Drawing"]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c8eddcc2f684a30fbdfd588")
}
> db.oppositeAddToSetDemo.insertOne({"StudentName":"Carol","StudentHobby":["Cricket","Dance","Hiking"]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c8eddfd2f684a30fbdfd589")
}
> db.oppositeAddToSetDemo.insertOne({"StudentName":"David","StudentHobby":["Learning","Photography"]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c8ede272f684a30fbdfd58a")
}使用 find() 方法顯示集合中的所有文件。查詢如下 -
> db.oppositeAddToSetDemo.find().pretty();
以下是輸出 -
{
"_id" : ObjectId("5c8eddcc2f684a30fbdfd588"),
"StudentName" : "John",
"StudentHobby" : [
"Cricket",
"Cooking",
"Drawing"
]
}
{
"_id" : ObjectId("5c8eddfd2f684a30fbdfd589"),
"StudentName" : "Carol",
"StudentHobby" : [
"Cricket",
"Dance",
"Hiking"
]
}
{
"_id" : ObjectId("5c8ede272f684a30fbdfd58a"),
"StudentName" : "David",
"StudentHobby" : [
"Learning",
"Photography"
]
}以下是使用 $pull 運算子對 $addToSet 的相反操作的查詢 -
> db.oppositeAddToSetDemo.update(
... {"StudentName": "John"},
... {$pull: { "StudentHobby": "Cooking"}});
WriteResult({ "nMatched" : 1, "nUpserted" : 0, "nModified" : 1 })讓我們使用 find() 檢查集合中的文件。查詢如下
> db.oppositeAddToSetDemo.find().pretty();
以下是輸出 -
{
"_id" : ObjectId("5c8eddcc2f684a30fbdfd588"),
"StudentName" : "John",
"StudentHobby" : [
"Cricket",
"Drawing"
]
}
{
"_id" : ObjectId("5c8eddfd2f684a30fbdfd589"),
"StudentName" : "Carol",
"StudentHobby" : [
"Cricket",
"Dance",
"Hiking"
]
}
{
"_id" : ObjectId("5c8ede272f684a30fbdfd58a"),
"StudentName" : "David",
"StudentHobby" : [
"Learning",
"Photography"
]
}
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