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法律研究Python 中的 Zip 函式用於更改為新的字元集。
給定一個 26 個字母的字元集，我們在這裡將使用一個新字元集。還有另一個字元集，就像字母表一樣 (a, b, c........z)，我們的任務是在新的字元集和該字母表之間建立聯絡。
示例
New character set: qwertyuiopasdfghjklzxcvbnm Input: "wwmm" Output: bbzy
演算法
Step 1: Given a new character set and input the string to make a relation. Step 2: and the original character set also given below. Step 3: Create a dictionary, we use here map technique, we map the English character set and new given character set, zip() does it for us. Both character sets are the map, here we match each character of given character set with each character of new charset sequentially. Step 4: iterate through the original string and get characters of an original character set. Step 5: join characters without space to get new string.
示例程式碼
# Function to change string to a new character
defnewString(cs,n):
ori = 'abcdefghijklmnopqrstuvwxyz'
newchar = dict(zip(cs,ori))
newstr = [newchar[chr] for chr in n]
print (''.join(newstr))
# Driver program
if __name__ == "__main__":
newcharSet = 'qwertyuiopasdfghjklzxcvbnm'
input = 'wwmn'
newString(newcharSet,input)
輸出
bbzy
更新於: 30-Jul-2019
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