MongoDB 子文件欄位求和?
您可以為此使用聚合框架。我們首先使用文件建立一個集合 -
> db.summingSubDocumentDemo.insertOne(
... { "_id" :101, "CustomerDetails" : { "CustomerPurchase" : { "CustomerPurchaseAmount" : 2000 } } });
{ "acknowledged" : true, "insertedId" : 101 }
> db.summingSubDocumentDemo.insertOne( { "_id" :102, "CustomerDetails" : { "CustomerPurchase" : { "CustomerPurchaseAmount" : 3000 } } });
{ "acknowledged" : true, "insertedId" : 102 }
> db.summingSubDocumentDemo.insertOne( { "_id" :103, "CustomerDetails" : { "CustomerPurchase" : { "CustomerPurchaseAmount" : 5000 } } });
{ "acknowledged" : true, "insertedId" : 103 }以下是使用 find() 方法顯示集合中所有文件的查詢 -
> db.summingSubDocumentDemo.find().pretty();
這將產生以下輸出 -
{
"_id" : 101,
"CustomerDetails" : {
"CustomerPurchase" : {
"CustomerPurchaseAmount" : 2000
}
}
}
{
"_id" : 102,
"CustomerDetails" : {
"CustomerPurchase" : {
"CustomerPurchaseAmount" : 3000
}
}
}
{
"_id" : 103,
"CustomerDetails" : {
"CustomerPurchase" : {
"CustomerPurchaseAmount" : 5000
}
}
}以下是求和 MongoDB 子文件欄位的查詢 -
> db.summingSubDocumentDemo.aggregate({$group : {_id: "",
... totalAmount : {$sum: "$CustomerDetails.CustomerPurchase.CustomerPurchaseAmount"}}},
... {$project: {_id: 0, totalAmount: 1}});這將產生以下輸出 -
{ "totalAmount" : 10000 }
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