根據月份從 MySQL 表中選擇總計
為此,你可以使用 GROUP BY MONTH()。讓我們先建立一個表 -
mysql> create table DemoTable1628 -> ( -> PurchaseDate date, -> Amount int -> ); Query OK, 0 rows affected (1.55 sec)
使用 insert 命令在表中插入一些記錄。
mysql> insert into DemoTable1628 values('2019-01-10',1500);
Query OK, 1 row affected (0.68 sec)
mysql> insert into DemoTable1628 values('2019-10-10',2000);
Query OK, 1 row affected (0.61 sec)
mysql> insert into DemoTable1628 values('2019-10-24',100);
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable1628 values('2019-11-10',500);
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable1628 values('2019-12-10',1600);
Query OK, 1 row affected (0.32 sec)
mysql> insert into DemoTable1628 values('2019-10-10',900);
Query OK, 1 row affected (0.47 sec)使用 select 語句顯示錶中的所有記錄 -
mysql> select * from DemoTable1628;
這將產生以下輸出 -
+--------------+--------+ | PurchaseDate | Amount | +--------------+--------+ | 2019-01-10 | 1500 | | 2019-10-10 | 2000 | | 2019-10-24 | 100 | | 2019-11-10 | 500 | | 2019-12-10 | 1600 | | 2019-10-10 | 900 | +--------------+--------+ 6 rows in set (0.00 sec)
以下是根據月份從資料庫表中獲取總計的查詢 -
mysql> select month(PurchaseDate) as Month,year(PurchaseDate) as Year,SUM(Amount) -> from DemoTable1628 -> group by month(PurchaseDate);
這將產生以下輸出 -
+-------+------+-------------+ | Month | Year | SUM(Amount) | +-------+------+-------------+ | 1 | 2019 | 1500 | | 10 | 2019 | 3000 | | 11 | 2019 | 500 | | 12 | 2019 | 1600 | +-------+------+-------------+ 4 rows in set (0.20 sec)
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