Python程式:查詢具有常數差的最長算術子序列的長度
假設我們有一個數字列表nums和另一個值diff,我們需要找到最長算術子序列的長度,其中子序列中任何連續數字之間的差與diff相同。
因此,如果輸入類似於nums = [-1, 1, 4, 7, 2, 10] diff = 3,則輸出將為4,因為我們可以選擇像[1, 4, 7, 10]這樣的子序列。
為了解決這個問題,我們將遵循以下步驟:
- seen := 一個空字典,當鍵不存在時,預設值為0
- mx := 0
- 對於nums中的每個x,執行:
- 如果x - diff在seen中,則
- seen[x] := seen[x - diff] + 1
- 否則,
- seen[x] := 1
- mx := mx和seen[x]中的最大值
- 如果x - diff在seen中,則
- 返回mx
示例
讓我們看看下面的實現以更好地理解:
from collections import defaultdict def solve(nums, diff): seen = defaultdict(int) mx = 0 for x in nums: if x - diff in seen: seen[x] = seen[x - diff] + 1 else: seen[x] = 1 mx = max(mx, seen[x]) return mx nums = [-1, 1, 4, 7, 2, 10] diff = 3 print(solve(nums, diff))
輸入
[-1, 1, 4, 7, 2, 10], 3
輸出
4
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