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法律學列印單詞數、母音數以及每個字元出現的頻率
輸入一個字串，找到使用者輸入的單詞總數、母音數以及某個字元的出現頻率
Input : enter s string : I love my MOM Enter a charcter of which you want to find a frequency: M Total frequency of M : 2 Total number of vowels : 4 Total number of words : 4
演算法
START Step 1 Declare array of string, ch, i, freq to 0, vow to 0, word to 0 Step 2 Input a string and a character ch Step 3 Loop for from i to 0 and str[i]!=’\o’ and ++i Step 3.1 IF statement for ch==str[i] Post incrementing freq Step 3.2 End If Step 3.3 IF statement str[i]=='a'||str[i]=='e'||str[i]=='i'||str[i]=='o'||str[i]=='u'||str[i]=='A'||str[i]=='E'||str[i]=='I'||str[i]=='O'||str[i]=='U' Post incrementing vow Step 3.4 End If Step 3.5 IF statement str[i]=’ ’ Post incrementing word Step 3.6 End If Step 4 End For loop STOP
示例
#include <stdio.h>
int main() {
char str[1000], ch;
int i, freq=0, vow=0, word=0;
printf("Enter a string of your choice: ");
gets(str);
printf("Enter a character of which you want to find the frequency: ");
scanf("%c",&ch);
for(i = 0; str[i] != '\0'; ++i){
if(ch == str[i]) //to find the frequency of a character {
++freq;
}
if(str[i]=='a'||str[i]=='e'||str[i]=='i'||str[i]=='o'||str[i]=='u'||str[i]=='A'||str[i]=='E'||str[i]=='I'||str[i]=='O'||str[i]=='U') {
++vow; //to find the number of vowels
}
if (str[i] == ' ') {
word++; //to find the number of words
}
}
printf("Frequency of %c = %d", ch, freq);
printf("
total number of vowels in a string are %d " ,vow );
printf("
total number of words in a string are %d " ,word+1 );
return 0;
}輸出
如果我們執行以上程式，它將生成以下輸出。
Enter a string of your choice: I love PrograMMIng Enter a character of which you want to find the frequency: M Frequency of M = 2 total number of vowels in a string are 6 total number of words in a string are 3
更新於: 30-7-2019
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