在 MySQL 中使用 ORDER BY rand() 並在其中保持分組?
我們先建立一個表格 −
mysql> create table DemoTable -> ( -> StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY, -> StudentMarks int -> ); Query OK, 0 rows affected (0.58 sec)
使用 insert 命令在表格中插入一些記錄。我們還插入了重複的記錄 −
mysql> insert into DemoTable(StudentMarks) values(98); Query OK, 1 row affected (0.11 sec) mysql> insert into DemoTable(StudentMarks) values(98); Query OK, 1 row affected (0.10 sec) mysql> insert into DemoTable(StudentMarks) values(78); Query OK, 1 row affected (0.10 sec) mysql> insert into DemoTable(StudentMarks) values(78); Query OK, 1 row affected (0.29 sec) mysql> insert into DemoTable(StudentMarks) values(45); Query OK, 1 row affected (0.10 sec) mysql> insert into DemoTable(StudentMarks) values(56); Query OK, 1 row affected (0.09 sec)
使用 select 語句顯示錶格中的所有記錄 −
mysql> select *from DemoTable;
這將產生以下輸出 −
+-----------+--------------+ | StudentId | StudentMarks | +-----------+--------------+ | 1 | 98 | | 2 | 98 | | 3 | 78 | | 4 | 78 | | 5 | 45 | | 6 | 56 | +-----------+--------------+ 6 rows in set (0.00 sec)
以下是按 rand() 進行排序並保持分組的查詢 −
mysql> select *from DemoTable order by rand(StudentMarks*100*RAND());
這將產生以下輸出。此處,98 分記錄保持分組 −
+-----------+--------------+ | StudentId | StudentMarks | +-----------+--------------+ | 3 | 78 | | 6 | 56 | | 5 | 45 | | 4 | 78 | | 1 | 98 | | 2 | 98 | +-----------+--------------+ 6 rows in set (0.00 sec)
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