用於計算日期並獲取重複日期的 MySQL 查詢
要顯示計數,請使用聚合函式 COUNT(*)。我們首先建立一個表 -
mysql> create table DemoTable1321 -> ( -> ArrivalDatetime timestamp -> ); Query OK, 0 rows affected (0.50 sec)
示例
使用 insert 命令在表中插入一些記錄 -
mysql> insert into DemoTable1321 values(now());
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable1321 values('2019-01-10 12:34:00');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable1321 values('2019-06-12 11:34:00');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable1321 values('2019-06-12 04:50:00');
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable1321 values('2019-09-18 10:50:45');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable1321 values('2019-06-12 06:10:20');
Query OK, 1 row affected (0.11 sec)使用 select 語句從表中顯示所有記錄 -
mysql> select * from DemoTable1321;
輸出
+---------------------+ | ArrivalDatetime | +---------------------+ | 2019-09-18 21:49:17 | | 2019-01-10 12:34:00 | | 2019-06-12 11:34:00 | | 2019-06-12 04:50:00 | | 2019-09-18 10:50:45 | | 2019-06-12 06:10:20 | +---------------------+ 6 rows in set (0.00 sec)
示例
以下是用於計算日期的查詢 -
mysql> select date(ArrivalDatetime) as OnlyDate,count(*) as Total from DemoTable1321 -> group by date(ArrivalDatetime) -> order by date(ArrivalDatetime);
輸出
+------------+-------+ | OnlyDate | Total | +------------+-------+ | 2019-01-10 | 1 | | 2019-06-12 | 3 | | 2019-09-18 | 2 | +------------+-------+ 3 rows in set (0.00 sec)
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