MySQL 查詢,用於根據當前日期對日期之間的差值進行排序並顯示
為此,請使用 ORDER BY 子句。當前日期如下 −
mysql> select now(); +---------------------+ | now() | +---------------------+ | 2019-06-09 21:08:16 | +---------------------+ 1 row in set (0.00 sec)
讓我們先建立一個表 −
mysql> create table DemoTable -> ( -> Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, -> DueDate datetime -> ); Query OK, 0 rows affected (0.62 sec)
使用 insert 命令在表中插入一些記錄 −
mysql> insert into DemoTable(DueDate) values('2019-06-12');
Query OK, 1 row affected (0.24 sec)
mysql> insert into DemoTable(DueDate) values('2019-06-01');
Query OK, 1 row affected (0.37 sec)
mysql> insert into DemoTable(DueDate) values('2019-06-05');
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable(DueDate) values('2019-06-10');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable(DueDate) values('2019-06-11');
Query OK, 1 row affected (0.66 sec)使用 select 語句顯示錶中的所有記錄: −
mysql> select *from DemoTable;
輸出
+----+---------------------+ | Id | DueDate | +----+---------------------+ | 1 | 2019-06-12 00:00:00 | | 2 | 2019-06-01 00:00:00 | | 3 | 2019-06-05 00:00:00 | | 4 | 2019-06-10 00:00:00 | | 5 | 2019-06-11 00:00:00 | +----+---------------------+ 5 rows in set (0.00 sec)
以下是透過排序後的查詢得到日期差值並對日期進行排序。日期差值顯示在單獨的列中 −
mysql> select Id,DueDate,DATEDIFF(DueDate, CURDATE()) AS t from DemoTable -> order by CASE WHEN t < 0 THEN 1 ELSE 0 END, t;
輸出
+----+---------------------+------+ | Id | DueDate | t | +----+---------------------+------+ | 4 | 2019-06-10 00:00:00 | 1 | | 5 | 2019-06-11 00:00:00 | 2 | | 1 | 2019-06-12 00:00:00 | 3 | | 2 | 2019-06-01 00:00:00 | -8 | | 3 | 2019-06-05 00:00:00 | -4 | +----+---------------------+------+ 5 rows in set (0.00 sec)
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