MongoDB 查詢跳過前 n 個文件?
要跳過特定數量的文件,請將 skip() 與 limit 配合使用。讓我們建立一個包含文件的集合 −
> db.demo246.insertOne({"StudentFirstName":"Chris","StudentLastName":"Brown"}); { "acknowledged" : true, "insertedId" : ObjectId("5e46b0d71627c0c63e7dba65") } > db.demo246.insertOne({"StudentFirstName":"John","StudentLastName":"Doe"}); { "acknowledged" : true, "insertedId" : ObjectId("5e46b0e21627c0c63e7dba66") } > db.demo246.insertOne({"StudentFirstName":"John","StudentLastName":"Smith"}); { "acknowledged" : true, "insertedId" : ObjectId("5e46b0ea1627c0c63e7dba67") } > db.demo246.insertOne({"StudentFirstName":"Carol","StudentLastName":"Taylor"}); { "acknowledged" : true, "insertedId" : ObjectId("5e46b0f91627c0c63e7dba68") }
在 find() 方法的幫助下顯示集合中的所有文件 −
> db.demo246.find();
這會產生以下輸出 −
{ "_id" : ObjectId("5e46b0d71627c0c63e7dba65"), "StudentFirstName" : "Chris", "StudentLastName" : "Brown" } { "_id" : ObjectId("5e46b0e21627c0c63e7dba66"), "StudentFirstName" : "John", "StudentLastName" : "Doe" } { "_id" : ObjectId("5e46b0ea1627c0c63e7dba67"), "StudentFirstName" : "John", "StudentLastName" : "Smith" } { "_id" : ObjectId("5e46b0f91627c0c63e7dba68"), "StudentFirstName" : "Carol", "StudentLastName" : "Taylor" }
以下是 MongoDB 中跳過前 n 個文件的查詢 −
> db.demo246.find().skip(2).limit(1);
這會產生以下輸出 −
{ "_id" : ObjectId("5e46b0ea1627c0c63e7dba67"), "StudentFirstName" : "John", "StudentLastName" : "Smith" }
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