帶有分組查詢示例的 MongoDB 聚合框架?
為此,請使用 MongoDB 聚合中的 $group。我們使用文件建立一個集合 −
> db.demo639.insertOne( ... { ... "_id" : 1, ... "CountryName" : "US", ... "Info1" : { ... "Name" : "Chris", ... "SubjectName" : "MySQL", ... "Marks" : 78 ... }, ... "Info2" : { ... "Name" : "Chris", ... "SubjectName" : "MySQL", ... "Marks" : 78 ... } ... } ... ); { "acknowledged" : true, "insertedId" : 1 } > db.demo639.insertOne( ... { ... "_id" : 2, ... "CountryName" : "UK", ... "Info1" : { ... "Name" : "Chris", ... "SubjectName" : "MySQL", ... "Marks" : 79 ... }, ... "Info2" : { ... "Name" : "Chris", ... "SubjectName" : "MySQL", ... "Marks" : 88 ... } ... } ... ); { "acknowledged" : true, "insertedId" : 2 }
在 find() 方法的幫助下顯示集合中的所有文件 −
> db.demo639.find();
這將產生以下輸出 −
{ "_id" : 1, "CountryName" : "US", "Info1" : { "Name" : "Chris", "SubjectName" : "MySQL", "Marks" : 78 }, "Info2" : { "Name" : "Chris", "SubjectName" : "MySQL", "Marks" : 78 } } { "_id" : 2, "CountryName" : "UK", "Info1" : { "Name" : "Chris", "SubjectName" : "MySQL", "Marks" : 79 }, "Info2" : { "Name" : "Chris", "SubjectName" : "MySQL", "Marks" : 88 } }
下面是帶有 $group 查詢的聚合框架查詢 −
> db.demo639.aggregate({$group : {_id : {Name1:"$Info1.Name",Name2:"$Info2.Name"}, ... ... Marks:{$first:"$Info2.Marks"}, ... Marks:{$sum:"$Info2.Marks"} ... }}).pretty();
這將產生以下輸出 −
{ "_id" : { "Name1" : "Chris", "Name2" : "Chris" }, "Marks" : 166 }
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