如何在 MongoDB 中選擇其中的陣列只包含特定欄位的物件?
我們首先建立一個包含以下文件的集合:
> db.arrayContainOnlySpecificFieldDemo.insertOne( ... { ... "StudentName":"John", ... "StudentAge":21, ... "StudentTechnicalSubject":["C","Java","MongoDB"] ... } ... ); { "acknowledged" : true, "insertedId" : ObjectId("5cc4921dac184d684e3fa26a") } > db.arrayContainOnlySpecificFieldDemo.insertOne( { "StudentName":"Carol", "StudentAge":23, "StudentTechnicalSubject":["MongoDB"] } ); { "acknowledged" : true, "insertedId" : ObjectId("5cc49237ac184d684e3fa26b") }
在集合中顯示所有文件,可以在 find() 方法的幫助下進行。查詢如下:
> db.arrayContainOnlySpecificFieldDemo.find().pretty();
這將產生以下輸出:
{ "_id" : ObjectId("5cc4921dac184d684e3fa26a"), "StudentName" : "John", "StudentAge" : 21, "StudentTechnicalSubject" : [ "C", "Java", "MongoDB" ] } { "_id" : ObjectId("5cc49237ac184d684e3fa26b"), "StudentName" : "Carol", "StudentAge" : 23, "StudentTechnicalSubject" : [ "MongoDB" ] }
以下是選擇其中陣列只包含特定欄位的物件的查詢:
> db.arrayContainOnlySpecificFieldDemo.find({"StudentTechnicalSubject":[ "MongoDB"]}).pretty();
這將產生以下輸出:
{ "_id" : ObjectId("5cc49237ac184d684e3fa26b"), "StudentName" : "Carol", "StudentAge" : 23, "StudentTechnicalSubject" : [ "MongoDB" ] }
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