如何在 MongoDB 中改善查詢的執行時間?
要改善查詢的執行時間,請使用索引とともにユニーク:真。我們建立一個包含文件的集合 −
> db.demo193.createIndex({"LastName":1},{unique:true});
{
"createdCollectionAutomatically" : true,
"numIndexesBefore" : 1,
"numIndexesAfter" : 2,
"ok" : 1
}
> db.demo193.insertOne({"FirstName":"John","LastName":"Doe"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e3ade1803d395bdc21346d1")
}
> db.demo193.insertOne({"FirstName":"John","LastName":"Smith"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e3ade1f03d395bdc21346d2")
}
> db.demo193.insertOne({"FirstName":"David","LastName":"Miller"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e3ade2803d395bdc21346d3")
}使用 find() 方法從集合中顯示所有文件 −
> db.demo193.find();
這將生成以下輸出 −
{ "_id" : ObjectId("5e3ade1803d395bdc21346d1"), "FirstName" : "John", "LastName" : "Doe" }
{ "_id" : ObjectId("5e3ade1f03d395bdc21346d2"), "FirstName" : "John", "LastName" : "Smith" }
{ "_id" : ObjectId("5e3ade2803d395bdc21346d3"), "FirstName" : "David", "LastName" : "Miller" }以下是對價值的查詢with faster execution time −
> db.demo193.find({"LastName":"Smith"});這將生成以下輸出 −
{ "_id" : ObjectId("5e3ade1f03d395bdc21346d2"), "FirstName" : "John", "LastName" : "Smith" }
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