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法學如何在 R 中向量的字元中查詢相似的單詞？
有時字元向量中的字串會出現拼寫錯誤，而我們希望提取相似的單詞以避免拼寫錯誤，因為相似的單詞很可能代表單詞的正確和錯誤形式。這可以使用具有 lapply 函式的 agrep 來實現。
示例 1
x1<-c("India","United Kingdoms","Indiaa","Egyypt","United
Kingdom","Turkey","Egypt","Belaarus","Belarus")
lapply(x1,agrep,x1,value=TRUE)輸出
[[1]] [1] "India" "Indiaa" [[2]] [1] "United Kingdoms" "United Kingdom" [[3]] [1] "India" "Indiaa" [[4]] [1] "Egyypt" "Egypt" [[5]] [1] "United Kingdoms" "United Kingdom" [[6]] [1] "Turkey" [[7]] [1] "Egyypt" "Egypt" [[8]] [1] "Belaarus" "Belarus" [[9]] [1] "Belaarus" "Belarus"
示例 2
x2<-c("Alhadi","Umair","Omar","Alhadi","Shanti","Shant","Umaer","Peter","Rahul","Pattrick","P
eeter","Rahuls")
lapply(x2,agrep,x2,value=TRUE)輸出
[[1]] [1] "Al-hadi" "Alhadi" [[2]] [1] "Umair" "Umaer" [[3]] [1] "Omar" [[4]] [1] "Al-hadi" "Alhadi" [[5]] [1] "Shanti" "Shant" [[6]] [1] "Shanti" "Shant" [[7]] [1] "Umair" "Umaer" [[8]] [1] "Peter" "Peeter" [[9]] [1] "Rahul" "Rahuls" [[10]] [1] "Pattrick" [[11]] [1] "Peter" "Peeter" [[12]] [1] "Rahul" "Rahuls"
示例 3
x3<-c("Alabamaa","New Yorky","New
Yok","Alabma","Florida","Illinois","Texas","Illinoise")
lapply(x3,agrep,x3,value=TRUE)輸出
[[1]] [1] "Alabamaa" [[2]] [1] "New Yorky" [[3]] [1] "New Yorky" "New Yok" [[4]] [1] "Alabamaa" "Alabma" [[5]] [1] "Florida" [[6]] [1] "Illinois" "Illinoise" [[7]] [1] "Texas" [[8]] [1] "Illinois" "Illinoise"
更新時間: 09-Sep-2020
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