如何在 R 中組合列表?
當我們有多個列表,但它們的的資料型別相似時,我們可能需要合併這些列表。這將很有用,因為我們可以使用一個列表名稱執行計算,而不是將它們應用於多個列表中。我們可以使用 mapply 函式合併多個列表。
示例
考慮以下列表 -
> List1<-list(letters[1:5],1:5,5:1,25,c("A","B","C","D"))
> List1
[[1]]
[1] "a" "b" "c" "d" "e"
[[2]]
[1] 1 2 3 4 5
[[3]]
[1] 5 4 3 2 1
[[4]]
[1] 25
[[5]]
[1] "A" "B" "C" "D"
> List2<-list(letters[6:10],6:10,c(25,16,9,4,1),36,c("Andy","Boston","Caroline","Dinesh"))
> List2
[[1]]
[1] "f" "g" "h" "i" "j"
[[2]]
[1] 6 7 8 9 10
[[3]]
[1] 25 16 9 4 1
[[4]]
[1] 36
[[5]]
[1] "Andy" "Boston" "Caroline" "Dinesh"
> mapply(c, List1, List2, SIMPLIFY=FALSE)
[[1]]
[1] "a" "b" "c" "d" "e" "f" "g" "h" "i" "j"
[[2]]
[1] 1 2 3 4 5 6 7 8 9 10
[[3]]
[1] 5 4 3 2 1 25 16 9 4 1
[[4]]
[1] 25 36
[[5]]
[1] "A" "B" "C" "D" "Andy" "Boston" "Caroline" "Dinesh"現在假設我們還有一個 List3,那麼可以按如下所示將其合併 -
> List3<-list(letters[11:15],11:15,c(6,7,8,9,10),49,c("Aaron","Betty","Corie","Donald"))
> List3
[[1]]
[1] "k" "l" "m" "n" "o"
[[2]]
[1] 11 12 13 14 15
[[3]]
[1] 6 7 8 9 10
[[4]]
[1] 49
[[5]]
[1] "Aaron" "Betty" "Corie" "Donald"
> mapply(c, List1, List2, List3, SIMPLIFY=FALSE)
[[1]]
[1] "a" "b" "c" "d" "e" "f" "g" "h" "i" "j" "k" "l" "m" "n" "o"
[[2]]
[1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
[[3]]
[1] 5 4 3 2 1 25 16 9 4 1 6 7 8 9 10
[[4]]
[1] 25 36 49
[[5]]
[1] "A" "B" "C" "D" "Andy" "Boston" "Caroline" "Dinesh" "Aaron" "Betty" "Corie" "Donald"
廣告
資料結構
網路
RDBMS
作業系統
Java
iOS
HTML
CSS
Android
Python
C 程式設計
C++
C#
MongoDB
MySQL
Javascript
PHP