C# 程式接收兩個整數並返回餘數
首先,設定兩個數字。
int one = 250; int two = 200;
現在將這些數字傳遞給以下函式。
public int RemainderFunc(int val1, int val2) {
if (val2 == 0)
throw new Exception("Second number cannot be zero! Cannot divide by zero!");
if (val1 < val2)
throw new Exception("Number cannot be less than the divisor!");
else
return (val1 % val2);
}上面我們檢查了兩個條件,即
- 如果第二個數字為零,則會發生異常。
- 如果第一個數字小於第二個數字,則會發生異常。
要返回兩個數字的餘數,以下是完整程式碼。
示例
using System;
namespace Program {
class Demo {
public int RemainderFunc(int val1, int val2) {
if (val2 == 0)
throw new Exception("Second number cannot be zero! Cannot divide by zero!");
if (val1 < val2)
throw new Exception("Number cannot be less than the divisor!");
else
return (val1 % val2);
}
static void Main(string[] args) {
int one = 250;
int two = 200;
int remainder;
Console.WriteLine("Number One: "+one);
Console.WriteLine("Number Two: "+two);
Demo d = new Demo();
remainder = d.RemainderFunc(one, two);
Console.WriteLine("Remainder: {0}", remainder );
Console.ReadLine();
}
}
}輸出
Number One: 250 Number Two: 200 Remainder: 50
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