如果 UPDATE 語句的 SET 子句中用於指定新值的子查詢未返回任何行,MySQL 將返回什麼?
在這種情況下,MySQL將向 SET 子句提供一個 NULL 值。以下示例將演示它−
示例
mysql> Select * from student; +----+---------+-----------+ | Id | Name | grade | +----+---------+-----------+ | 1 | Rahul | Good | | 2 | Gaurav | Good | | 3 | Raman | Excellent | | 4 | Harshit | Average | | 5 | Aarav | Best | | 6 | Ram | average | +----+---------+-----------+ 6 rows in set (0.00 sec) mysql> select * from info; +------+-----------+ | id | remarks | +------+-----------+ | 1 | Good | | 2 | Good | | 3 | Excellent | | 4 | Average | | 5 | Best | +------+-----------+ 5 rows in set (0.00 sec)
從上述兩張表中,我們可以看到“學生”表中有6行,並且在 id = 6 的情況下,“成績”的值為“平均”,而“資訊”表中有5行。現在,在以下查詢中使用的子查詢將不會提供任何行來在 SET 子句中提供新值,因此它將插入一個 NULL 值。可以從以下查詢的輸出中檢查它−
mysql> UPDATE STUDENT SET grade = (SELECT remarks from info WHERE info.id = student.id) WHERE id = 6; Query OK, 1 row affected (0.04 sec) Rows matched: 1 Changed: 1 Warnings: 0 mysql> Select * from student; +----+---------+-----------+ | Id | Name | grade | +----+---------+-----------+ | 1 | Rahul | Good | | 2 | Gaurav | Good | | 3 | Raman | Excellent | | 4 | Harshit | Average | | 5 | Aarav | Best | | 6 | Ram | NULL | +----+---------+-----------+ 6 rows in set (0.00 sec)
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