Java 中的 AbstractSequentialList 的 indexOf() 方法
indexOf() 方法從 AbstractList 類繼承而來。它用於返回該列表中指定元素的第一次出現的索引。如果列表為空,則返回 -1。
語法如下 −
public int indexOf(Object ele)
此處 ele 是你想要索引的元素。
若要在 Java 中使用 AbstractSequentialList 類,你需要匯入以下軟體包 −
import java.util.AbstractSequentialList;
以下是一個在 Java 中實現 AbstractSequentialList indexOf() 方法的示例 −
示例
import java.util.LinkedList;
import java.util.AbstractSequentialList;
public class Demo {
public static void main(String[] args) {
AbstractSequentialList<Integer> absSequential = new LinkedList<>();
absSequential.add(110);
absSequential.add(320);
absSequential.add(400);
absSequential.add(550);
absSequential.add(600);
absSequential.add(700);
absSequential.add(900);
System.out.println("Elements in the AbstractSequentialList = "+absSequential);
System.out.println("Elements in the AbstractSequentialList = "+absSequential.indexOf(550));
}
}輸出
Elements in the AbstractSequentialList = [110, 320, 400, 550, 600, 700, 900] Elements in the AbstractSequentialList = 3
我們看另一個元素不存在的示例 −
示例
import java.util.LinkedList;
import java.util.AbstractSequentialList;
public class Demo {
public static void main(String[] args) {
AbstractSequentialList<Integer> absSequential = new LinkedList<>();
absSequential.add(110);
absSequential.add(320);
absSequential.add(400);
absSequential.add(550);
absSequential.add(600);
absSequential.add(700);
absSequential.add(900);
System.out.println("Elements in the AbstractSequentialList = "+absSequential);
System.out.println("Elements in the AbstractSequentialList = "+absSequential.indexOf(10));
}
}輸出
Elements in the AbstractSequentialList = [110, 320, 400, 550, 600, 700, 900] Elements in the AbstractSequentialList = -1
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