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Legal Studies遞迴平 JavaScript 物件
我們需要編寫一個執行以下轉換的函式-
如果輸入物件為-
const input = {
a: 0,
b: {x: {y: 1, z: 2}},
c: 3
};那麼函式的輸出應該是-
const output = {
a: 0,
'b.x.y': 1,
'b.x.z': 2,
c: 3
}我們基本上必須編寫一個扁平化巢狀物件的函式。透過遞迴實現，實現程式碼如下-
示例
const obj = {
a: 1,
b: {x: {y: 1, z: 2}},
c: 3
};
const obj1 = {
a: 0,
b: 0,
c: 0
};
const object = { a: 0, b: { x: { y: 1, z: 2 } }, c: 3 };
const stringifyKeys = (obj, str = '', fresh = {}) => {
const keys = Object.keys(obj);
for(let i = 0; i < keys.length; i++){
if(typeof obj[keys[i]] === "object" && !Array.isArray(obj[keys[i]])
&& obj[keys[i]]){
stringifyKeys(obj[keys[i]], str+`${keys[i]}.`, fresh);
}else{
fresh[str+keys[i]] = obj[keys[i]];
};
}
return fresh;
};
console.log(stringifyKeys(obj));
console.log(stringifyKeys(object));
console.log(stringifyKeys(obj1));輸出
控制檯中的輸出將為-
{ a: 1, 'b.x.y': 1, 'b.x.z': 2, c: 3 }
{ a: 0, 'b.x.y': 1, 'b.x.z': 2, c: 3 }
{ a: 0, b: 0, c: 0 }
更新時間: 2020-08-26
304 次瀏覽
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