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法律研究Python - 遍歷元組列表
列表是一個重要的容器，在日常程式設計和 Web 開發中幾乎在每個程式碼中都會使用，使用得越多，掌握它的要求就越高，因此瞭解其操作非常有必要。
示例
# using itertools.ziplongest
# import library
from itertools import zip_longest
# initialising listoflist
test_list = [
[('11'), ('12'), ('13')],
[('21'), ('22'), ('23')],
[('31'), ('32'), ('33')]
]
# printing intial list
print ("Initial List = ", test_list)
# iterate list tuples list of list into single list
res_list = [item for my_list in zip_longest(*test_list)
for item in my_list if item]
# print final List
print ("Resultant List = ", res_list)
# using itertools.ziplongest + lambda + chain
# import library
from itertools import zip_longest, chain
# initialising listoflist
test_list = [
[('11'), ('12'), ('13')],
[('21'), ('22'), ('23')],
[('31'), ('32'), ('33')]
]
# printing intial list
print ("Initial List = ", test_list)
# iterate list tuples list of list into single list
# using lambda + chain + filter
res_list = list(filter(lambda x: x, chain(*zip_longest(*test_list))))
# print final List
print ("Resultant List = ", res_list)
# list using list comprehension
# initialising listoflist
test_list = [
[('11'), ('12'), ('13')],
[('21'), ('22'), ('23')],
[('31'), ('32'), ('33')]
]
# printing intial list
print ("Initial List = ", test_list)
# iterate list tuples list of list into single list
# using list comprehension
res_list = [item for list2 in test_list for item in list2]
# print final List
print ("Resultant List = ", res_list)
更新於：2020-08-06
144 次瀏覽
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