如果103 cm3的鋁的質量為0.280 Kg。求其密度 (a.) g/cm3 (b.) Kg/m3
答案:
體積 = 103 cm^3 = 103/1000000 = 0.000103 m^3
質量 = 0.280 Kg= 280 g
密度(g/cm^3)= 質量/體積 = 280 g/103 cm^3 = 2.72 g/cm^3
密度(kg/m^3)= 0.280 /0.000103 = 280/0.103 = 2720 Kg /m^3
廣告
答案:
體積 = 103 cm^3 = 103/1000000 = 0.000103 m^3
質量 = 0.280 Kg= 280 g
密度(g/cm^3)= 質量/體積 = 280 g/103 cm^3 = 2.72 g/cm^3
密度(kg/m^3)= 0.280 /0.000103 = 280/0.103 = 2720 Kg /m^3