JavaScript 中的物件差異
我們需要編寫一個 JavaScript 函式,該函式接受兩個物件(可能是巢狀的)並返回一個新物件,其中包含第一個物件中存在但第二個物件中不存在的鍵值對
讓我們為這個函式編寫程式碼 −
示例
const obj1 = { "firstName": "Raghav", "lastName": "Raj", "age": 43, "address": "G-12 Kalkaji", "email": "raghavraj1299@yahoo.com", "salary": 90000 }; const obj2 = { "lastName": "Raj", "address": "G-12 Kalkaji", "email": "raghavraj1299@yahoo.com", "salary": 90000 }; const objectDifference = (first, second) => { return Object.keys(first).reduce((acc, val) => { if(!second.hasOwnProperty(val)){ acc[val] = first[val]; }; return acc; }, {}); }; console.log(objectDifference(obj1, obj2));
輸出
控制檯中的輸出將為 −
{ firstName: 'Raghav', age: 43 }
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