使用空值來獲取資料的 MySQL 選擇查詢?


我們首先建立一個表-

mysql> create table DemoTable
(
   CustomerName varchar(100),
   CustomerCountryName varchar(100)
);
Query OK, 0 rows affected (0.95 sec)

使用插入命令在表中插入一些記錄-

mysql> insert into DemoTable values('Chris','US');
Query OK, 1 row affected (0.18 sec)
mysql> insert into DemoTable values('Bob','UK');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('Carol',NULL);
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable values('David','AUS');
Query OK, 1 row affected (0.32 sec)
mysql> insert into DemoTable values('Mike',NULL);
Query OK, 1 row affected (0.18 sec)

使用選擇語句從表中顯示所有記錄-

mysql> select *from DemoTable;

這將產生以下輸出-

+--------------+---------------------+
| CustomerName | CustomerCountryName |
+--------------+---------------------+
| Chris        | US                  |
| Bob          | UK                  |
| Carol        | NULL                |
| David        | AUS                 |
| Mike         | NULL                |
+--------------+---------------------+
5 rows in set (0.00 sec)

以下是使用空值獲取資料的查詢-

mysql> select *from DemoTable where CustomerCountryName IS NULL;

這將產生以下輸出-

+--------------+---------------------+
| CustomerName | CustomerCountryName |
+--------------+---------------------+
| Carol        | NULL                |
| Mike         | NULL                |
+--------------+---------------------+
2 rows in set (0.00 sec)

更新於: 30-Sep-2019

422 次檢視

事業騰飛

完成課程後獲得認證

開始
廣告
© . All rights reserved.