C# 中的 Math.Min() 方法


C# 中的 Math.Min() 方法用於返回兩個指定數字中較大的一個。此方法適用於數字為 Double、Decimal、Int16、Int32 等的情況。

語法

以下為語法 −

public static ulong Min (ulong val1, ulong val2);
public static uint Min (uint val1, uint val2);
public static ushort Min (ushort val1, ushort val2);
public static float Min (float val1, float val2);
public static byte Min (byte val1, byte val2);
public static long Min (long val1, long val2);

示例

現在讓我們看一個實現 Math.Min() 方法的示例 −

using System;
public class Demo {
   public static void Main(){
      byte val1 = 10, val2 = 15;
      decimal val3 = 1000M, val4 = 1500M;
      double val5 = 15.896745, val6 = 25.676843;
      short val7 = 20, val8 = 30;
      Console.WriteLine("Minimum Value from two byte values = "+Math.Min(val1, val2));
      Console.WriteLine("Minimum Value from two decimal values = "+Math.Min(val3, val4));
      Console.WriteLine("Minimum Value from two double values = "+Math.Min(val5, val6));
      Console.WriteLine("Minimum Value from two short values = "+Math.Min(val7, val8));
   }
}

輸出

將產生以下輸出 −

Minimum Value from two byte values = 10
Minimum Value from two decimal values = 1000
Minimum Value from two double values = 15.896745
Minimum Value from two short values = 20

示例

讓我們看另一個實現 Math.Min() 方法的示例 −

using System;
public class Demo {
   public static void Main(){
      int val1 = 10, val2 = 15;
      float val3 = 12.8f, val4 = 25.6f;
      Console.WriteLine("Minimum Value from two int values = "+Math.Min(val1, val2));
      Console.WriteLine("Minimum Value from two float values = "+Math.Min(val3, val4));
   }
}

輸出

將產生以下輸出 −

Minimum Value from two int values = 10
Minimum Value from two float values = 12.8

更新於: 06-11-2019

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