用單次迭代獲取連結串列中間元素的 Java 程式


在本文中,我們將瞭解如何透過單次迭代獲得 LinkedList 的中間元素。 java.util.LinkedList 類操作執行我們對雙向連結串列所期望的操作。對列表進行索引的操作將從開頭或結尾遍歷列表,以距離指定索引更近的方式進行。

下面是相同的演示 −

假設我們的輸入是

Input linked list: 100 200 330

期望的輸出將是

The middle element of the list is: 200

演算法

Step 1 - START
Step 2 - Declare a LinkedList namely input_list. Declare five node objects namely head, first_node, second_node, pointer_1, pointer_2.
Step 3 - Define the values.
Step 4 - Using a while loop, iterate over the linked list, get the middle element by traversing the list using pointer_1 and pointer_2 until pointer_1.next is not null.
Step 5 - Display the pointer_2 value as result.
Step 6 - Stop

示例 1

在這裡,我們在“main”函式下繫結所有操作。

public class LinkedList {
   Node head;
   static class Node {
      int value;
      Node next;
      Node(int d) {
         value = d;
         next = null;
      }
   }
   public static void main(String[] args) {
      LinkedList input_list = new LinkedList();
      input_list.head = new Node(100);
      Node second_node = new Node(200);
      Node third_node = new Node(330);
      input_list.head.next = second_node;
      second_node.next = third_node;
      Node current_node = input_list.head;
      System.out.print("The linked list is defined as: " );
      while (current_node != null) {
         System.out.print(current_node.value + " ");
         current_node = current_node.next;
      }
      Node pointer_1 = input_list.head;
      Node pointer_2 = input_list.head;
      while (pointer_1.next != null) {
         pointer_1 = pointer_1.next;
         if(pointer_1.next !=null) {
            pointer_1 = pointer_1.next;
            pointer_2 = pointer_2.next;
         }
      }
      System.out.println("\nThe middle element of the list is: " + pointer_2.value);
   }
}

輸出

The linked list is defined as: 100 200 330
The middle element of the list is: 200

示例 2

在這裡,我們將操作封裝到展示面向物件程式設計的函式中。

public class LinkedList {
   Node head;
   static class Node {
      int value;
      Node next;
      Node(int d) {
         value = d;
         next = null;
      }
   }
   static void get_middle_item(LinkedList input_list){
      Node pointer_1 = input_list.head;
      Node pointer_2 = input_list.head;
      while (pointer_1.next != null) {
         pointer_1 = pointer_1.next;
         if(pointer_1.next !=null) {
            pointer_1 = pointer_1.next;
            pointer_2 = pointer_2.next;
         }
      }
      System.out.println("\nThe middle element of the list is: " + pointer_2.value);
   }
   public static void main(String[] args) {
      LinkedList input_list = new LinkedList();
      input_list.head = new Node(100);
      Node second_node = new Node(200);
      Node third_node = new Node(330);
      input_list.head.next = second_node;
      second_node.next = third_node;
      Node current_node = input_list.head;
      System.out.print("The linked list is defined as: " );
      while (current_node != null) {
         System.out.print(current_node.value + " ");
         current_node = current_node.next;
      }
      get_middle_item(input_list);
   }
}

輸出

The linked list is defined as: 100 200 330
The middle element of the list is: 200

更新於:2022-3 月 30 日

172次瀏覽

開啟您的職業生涯

完成課程並獲得認證

開始
廣告