IntBuffer compareTo() 方法在 Java 中


可以使用 java.nio.IntBuffer 類中的 compareTo() 方法將緩衝區與另一個緩衝區進行比較。如果緩衝區小於給定的緩衝區,此方法將返回一個負整數,如果緩衝區與給定的緩衝區相等,則返回零,如果緩衝區大於給定的緩衝區,則返回一個正整數。

演示這一點的程式如下所示 −

示例

 現場演示

import java.nio.*;
import java.util.*;
public class Demo {
   public static void main(String[] args) {
      int n = 5;
      try {
         IntBuffer buffer1 = IntBuffer.allocate(n);
         buffer1.put(8);
         buffer1.put(1);
         buffer1.put(3);
         buffer1.put(7);
         buffer1.put(5);
         buffer1.rewind();
         System.out.println("The first IntBuffer is: " + Arrays.toString(buffer1.array()));
         IntBuffer buffer2 = IntBuffer.allocate(n);
         buffer2.put(8);
         buffer2.put(1);
         buffer2.put(3);
         buffer2.put(7);
         buffer2.put(5);
         buffer2.rewind();
         System.out.println("The second IntBuffer is: " + Arrays.toString(buffer2.array()));
         int val = buffer1.compareTo(buffer2);
         if (val == 0)
            System.out.println("
Both the buffers are lexicographically equal");          else if (val > 0)             System.out.println("
The first buffer is lexicographically greater than the second buffer");          else             System.out.println("
The second buffer is lexicographically greater than the first buffer");       } catch (IllegalArgumentException e) {          System.out.println("Error!!! IllegalArgumentException");       } catch (ReadOnlyBufferException e) {          System.out.println("Error!!! ReadOnlyBufferException");       }    } }

以上程式的輸出如下 −

輸出

The first IntBuffer is: [8, 1, 3, 7, 5]
The second IntBuffer is: [8, 1, 3, 7, 5]
Both the buffers are lexicographically equal

更新於: 30-Jul-2019

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