如何按照最短到最長的模式用 Java 對字串陣列進行排序


首先,我們建立一個字串陣列

String[] strArr = { "ABCD", "AB", "ABCDEFG", "ABC", "A", "ABCDE", "ABCDEF", "ABCDEFGHIJ" };

現在,針對最短到最長的模式(例如 A、AB、ABC、ABC 等),獲取兩個字串陣列的長度並按如下方式操作

Arrays.sort(strArr, (str1, str2) -> str1.length() - str2.length());

以下是一個按照最短到最長的模式對字串陣列排序的示例

示例

import java.util.Arrays;
public class Demo {
   public static void main(String[] args) {
      String[] strArr = { "ABCD", "AB", "ABCDEFG", "ABC", "A", "ABCDE", "ABCDEF","ABCDEFGHIJ" };
      System.out.println("Sorting array on the basis of their lengths (shortest to longest) =");
      Arrays.sort(strArr, (str1, str2) -> str1.length() - str2.length());
      Arrays.asList(strArr).forEach(System.out::println);
   }
}

輸出

Sorting array on the basis of their lengths (shortest to longest) =
A
AB
ABC
ABCD
ABCDE
ABCDEF
ABCDEFG
ABCDEFGHIJ

更新於: 30-Jul-2019

709 次檢視

開啟你的 職業 生涯

透過完成課程獲得認證

開始吧
廣告
© . All rights reserved.