如何防止 MySQL GROUP BY 將 NULL 值摺疊到單行中?
要實現這一目標,可將 IFNULL() 與 ORDER BY 子句結合使用。我們先建立一個名為表 table 的表 -
mysql> create table DemoTable1511 -> ( -> Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, -> FirstName varchar(20) -> ); Query OK, 0 rows affected (1.97 sec)
使用 insert 命令將一些記錄插入表中 -
mysql> insert into DemoTable1511(FirstName) values('John');
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable1511(FirstName) values('Robert');
Query OK, 1 row affected (0.29 sec)
mysql> insert into DemoTable1511(FirstName) values('Mike');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable1511(FirstName) values('Robert');
Query OK, 1 row affected (1.08 sec)
mysql> insert into DemoTable1511(FirstName) values(NULL);
Query OK, 1 row affected (0.68 sec)
mysql> insert into DemoTable1511(FirstName) values(NULL);
Query OK, 1 row affected (1.91 sec)
mysql> insert into DemoTable1511(FirstName) values('Mike');
Query OK, 1 row affected (0.51 sec)使用 select 語句顯示錶中的所有記錄 -
mysql> select * from DemoTable1511;
這將生成以下輸出 -
+----+-----------+ | Id | FirstName | +----+-----------+ | 1 | John | | 2 | Robert | | 3 | Mike | | 4 | Robert | | 5 | NULL | | 6 | NULL | | 7 | Mike | +----+-----------+ 7 rows in set (0.00 sec)
以下是對 MySQL GROUP BY 進行查詢以防止將 NULL 值摺疊到單行的方法 -
mysql> select min(Id) as Id,FirstName from DemoTable1511 group by FirstName,ifnull(FirstName,Id) order by Id;
這將生成以下輸出 -
+------+-----------+ | Id | FirstName | +------+-----------+ | 1 | John | | 2 | Robert | | 3 | Mike | | 5 | NULL | | 6 | NULL | +------+-----------+ 5 rows in set (0.00 sec)
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