如何在 MongoDB 中限制欄位返回的字元數?
要限制從 MongoDB 欄位返回的字元數,請使用 $substr。讓我們建立一個包含文件的集合 -
> db.demo233.insertOne({"Paragraph":"My Name is John Smith.I am learning MongoDB database"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e41877df4cebbeaebec5146")
}
> db.demo233.insertOne({"Paragraph":"David Miller is a good student and learning Spring and Hibernate Framework."});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e4187d7f4cebbeaebec5147")
}藉助 find() 方法顯示集合中的所有文件 -
> db.demo233.find().pretty();
這將產生以下輸出 -
{
"_id" : ObjectId("5e41877df4cebbeaebec5146"),
"Paragraph" : "My Name is John Smith.I am learning MongoDB database"
}
{
"_id" : ObjectId("5e4187d7f4cebbeaebec5147"),
"Paragraph" : "David Miller is a good student and learning Spring and Hibernate Framework."
}以下是限制 MongoDB 中欄位返回的字元數的查詢 -
> db.demo233.aggregate(
... [
... {
... $project:
... {
... Paragraph: { $substr: [ "$Paragraph", 0, 10] }
...
... }
...} ] )這將產生以下輸出 -
{ "_id" : ObjectId("5e41877df4cebbeaebec5146"), "Paragraph" : "My Name is" }
{ "_id" : ObjectId("5e4187d7f4cebbeaebec5147"), "Paragraph" : "David Mill" }
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