如何向 MongoDB 中插入布林欄位?


由於布林型別的變數只有兩個值:true 和 false,因此,在 MongoDB 中使用 true 和 false 關鍵字。我們建立一個包含文件的集合 -

> 
db.demo215.insertOne({"EmployeeDetails":[{EmployeeName:"David","isMarried":false,"Salary":56000}]});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5e3e344003d395bdc2134708")
}
> db.demo215.insertOne({"EmployeeDetails":[{EmployeeName:"Bob","isMarried":true,"Salary":60000}]});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5e3e344d03d395bdc2134709")
}
> db.demo215.insertOne({"EmployeeDetails":[{EmployeeName:"Chris","isMarried":false,"Salary":78000}]});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5e3e345a03d395bdc213470a")
}
> db.demo215.insertOne({"EmployeeDetails":[{EmployeeName:"Mike","isMarried":true,"Salary":17000}]});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5e3e346f03d395bdc213470b")
}

使用 find() 方法從集合中顯示所有文件 -

> db.demo215.find();

這將生成以下輸出 -

{ "_id" : ObjectId("5e3e344003d395bdc2134708"), "EmployeeDetails" : [ { "EmployeeName" : "David", "isMarried" : false, "Salary" : 56000 } ] }
{ "_id" : ObjectId("5e3e344d03d395bdc2134709"), "EmployeeDetails" : [ { "EmployeeName" : "Bob", "isMarried" : true, "Salary" : 60000 } ] }
{ "_id" : ObjectId("5e3e345a03d395bdc213470a"), "EmployeeDetails" : [ { "EmployeeName" : "Chris", "isMarried" : false, "Salary" : 78000 } ] }
{ "_id" : ObjectId("5e3e346f03d395bdc213470b"), "EmployeeDetails" : [ { "EmployeeName" : "Mike", "isMarried" : true, "Salary" : 17000 } ] }

更新於: 30-Mar-2020

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